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Precalc April W4: hyperbolas and parabolas

Authored by Tiffany Sims

Other

12th Grade - University

CCSS covered

Used 17+ times

Precalc April W4: hyperbolas and parabolas
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12 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What type of graph is this?

Hyperbola

Exponential

Linear function

Parabola

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What type of graph is this?

Hyperbola

Exponential

Linear function

Parabola

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the equation describing the relationship between dimensions and foci of a hyperbola?

c2 = a2 + b2
c2 = a2 - b2
4p
(x-h)2 + (y-k)2 = r2

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Is the hyperbola vertical or horizontal? 

Vertical
Horizontal

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A hyperbola has vertices (±5, 0) and one focus at (6, 0). What is the equation of the hyperbola in standard form?

x²/25 + y²/11 = 1
x²/5 - y²/11 = 1
x²/11- y²/25 = 1
x²/25 - y²/11= 1

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

What is the center of the hyperbola?

(0, 4)
(4, 0)
(-4, 0)
(0, -4)

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Write in standard form,  x24y2+10x+32y75=0x^2-4y^2+10x+32y-75=0  

 \frac{\left(y-4\right)^2}{36}-\frac{\left(x+5\right)^2}{9}=1  

 (y4)29(x+5)236=1\frac{\left(y-4\right)^2}{9}-\frac{\left(x+5\right)^2}{36}=1  

 (y4)29(x5)236=1\frac{\left(y-4\right)^2}{9}-\frac{\left(x-5\right)^2}{36}=1  

 (x+5)236(y4)29=1\frac{\left(x+5\right)^2}{36}-\frac{\left(y-4\right)^2}{9}=1  

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