Solving Log Equations

Log with a base "e" (log_e) is the same thing as...

• "e"
• Natural Logarithm (LN)
• Common Logarithm (Log)
• Natural Log, base "e"
  LN_e

Tags

CCSS.HSF.BF.B.5

Solve log(x) + log(x+3) = 1

• 5
• -2
• -5
• 2

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

log₂(x + 2) + log₂x  = 3

• -4, 2
• -2, 4
• 2
• 1

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

log₅(4x-7)=log₅(x+5)

• 3
• 12
• 4
• 7

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Solve

• A
• B
• C
• D

Tags

CCSS.HSA.REI.A.1

Find x: log_x(25) = 2

• x = 1

• x = 12.5

• No Solution

• x = 5

Tags

CCSS.HSF.BF.B.5

Find x: log₅(x) = 0

• No Solution

• x = 0

• x = 5

• x = 1

Tags

CCSS.HSF.BF.B.5

Solve.

9(e^x) - 31 =23

• x = 1.79

• x = 4.21

• x = -3.5

• x = 1.27

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.LE.A.4

Solve:

log (x - 1) - log (x - 2) = log 5

• 7

• 4/9

• 9/4

• 1/7

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

Rewrite the exponential as a log.

2^3x+1 = 12

• ln(2)= 3x+1

• log₂(12)= 3x+1

• ln(6)=3x+1

• log₁₂(2)= 3x+1

Tags

CCSS.HSF.BF.B.5