Identifying Trig Ratios

Identify the ratio for the tangent function

• $\frac{adjacent}{hypotenuse}$

• $\frac{opposite}{hypotenuse}$

• $\frac{opposite}{adjacent}$

• $\frac{hypotenuse}{adjacent}$

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

CCSS.HSF.TF.A.3

Identify the trigonometric function that is equal to the side ratio:  $\frac{opposite}{adjacent}$  

• tangent

• cosine

• sine

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Identify the trigonometric function that is equal to the side ratio:  $\frac{adjacent}{hypotenuse}$  

• tangent

• cosine

• sine

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Identify the ratio for the sine function

• $\frac{adjacent}{hypotenuse}$

• $\frac{opposite}{hypotenuse}$

• $\frac{opposite}{adjacent}$

• $\frac{hypotenuse}{adjacent}$

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the trigonometric ratio of SinQ.

Answer should be a fraction in simplest form!

• $SinQ=\frac{8}{17}$

• $SinQ=\frac{15}{17}$

• $SinQ=\frac{15}{8}$

• $SinQ=\frac{8}{15}$

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the trigonometric ratio of CosQ.
Answer should be a fraction in simplest form!

•  $CosQ=\frac{8}{17}$ 

•  $CosQ=\frac{15}{17}$ 

•  $CosQ=\frac{15}{8}$ 

•  $CosQ=\frac{8}{15}$ 

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the trigonometric ratio of TanQ.
Answer should be a fraction in simplest form!

•  $TanQ=\frac{8}{17}$ 

•  $TanQ=\frac{15}{17}$ 

•  $TanQ=\frac{15}{8}$ 

•  $TanQ=\frac{8}{15}$ 

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the trigonometric ratio of SinR.

Answer should be a fraction in simplest form!

• $SinR=\frac{8}{17}$

• $SinR=\frac{15}{17}$

• $SinR=\frac{15}{8}$

• $SinR=\frac{17}{8}$

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the trigonometric ratio of CosR.
Answer should be a fraction in simplest form!

•  $CosR=\frac{17}{8}$ 

•  $CosR=\frac{15}{17}$ 

•  $CosR=\frac{15}{8}$ 

•  $CosR=\frac{8}{17}$ 

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8

Find the trigonometric ratio of TanR.
Answer should be a fraction in simplest form!

•  $TanR=\frac{8}{15}$ 

•  $TanR=\frac{15}{17}$ 

•  $TanR=\frac{15}{8}$ 

•  $TanR=\frac{8}{17}$ 

Tags

CCSS.HSG.SRT.C.6

CCSS.HSG.SRT.C.8