
Constant Rate of Change
Authored by mary salinas
Mathematics
7th - 9th Grade
CCSS covered
Used 20+ times

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11 questions
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1.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Cheese costs $4.45 per pound. Which equation best represents y, the total cost of x pounds of cheese?
x = 4.25 + y
x = 4.25y
y = 4.25 + x
y = 4.25x
2.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A pilot takes a taxi from the airport to a hotel. The taxi driver charges a $2.50 inital charge plus $2.65 per mile. Which equation can be used to find y, the total cost of the trip if x represents the number of miles of the trip?
y = 2.50x + 2.65
y = 2.65(x + 2.50)
y = 2.65x + 2.50
y = 2.65x - 2.50
3.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Jeremiah sells flowers for $2 each and a vase for $5. Which equation can be used to find y, the total cost of the flowers and vase if x represents the number of flowers?
y = 5x + 2
y = 2x + 5
y = 5x - 2
y = 2x - 5
4.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
Dakota is training for a marathon. The table shows the number of miles she ran over four weeks. What is the constant rate of change between the number of weeks and the the number of miles. (Hint weeks = x and miles = y) Use the formula k = y/x
1 mile per week
3 miles per week
5 miles per week
15 miles per week
Tags
CCSS.HSF-LE.A.1B
5.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
An airport starts allowing planes to take off at 6:00 a.m. Based on the table below, what is the constant rate of change between the time and the number of flights taking off at the airport? (Hint: time = x and Flights = y) Use k = y/x
2 flights per hour
9 flights per hour
18 flights per hour
27 flights per hour
6.
MULTIPLE CHOICE QUESTION
15 mins • 1 pt
A cheetah can run a constant speedfor up to one minute. A researcher timed a cheetah while it was running. Based on the times and distances below, how fast did the cheetah run? (Hint seconds is = x and feet is = to y) Use k = y/x
1.3 feet per second
3 feet per second
15 feet per second
19.5 feet per second
7.
MULTIPLE SELECT QUESTION
15 mins • 1 pt
What is the constant rate for the following table
y = 1/20x
y = 20x
y = 40x
y = 1/40x
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