Solving Trig Equations IV

Solving Trig Equations IV

11th - 12th Grade

18 Qs

quiz-placeholder

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Solving Trig Equations IV

Solving Trig Equations IV

Assessment

Quiz

Mathematics, Other

11th - 12th Grade

Easy

CCSS
HSF.TF.B.7, HSF.TF.C.8, HSF.TF.A.2

+1

Standards-aligned

Created by

Kathleen Devlin

Used 3+ times

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18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

If you were given the equation  cosθ=12\cos\theta=-\frac{1}{2} , which variable in the ordered pairs on the unit circle would you look at to find your answer?

x

y

None of the above

Both x and y

Tags

CCSS.HSF.TF.A.2

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

If you were given the equation

 sinθ=22\sin\theta=-\frac{\sqrt{2}}{2}  and you looked on your unit circle to find possible answers, in which two quadrants would you find them?

I and II

II and III

III and IV

IV and I

Tags

CCSS.HSF.TF.B.7

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 sin2θ=2cosθ+2\sin^2\theta=2\cos\theta+2  Which identity would you have to use to solve the following equation?

 cos(2θ)=cos2θsin2θ\cos\left(2\theta\right)=\cos^2\theta-\sin^2\theta  

 sin(2θ)=2sinθcosθ\sin\left(2\theta\right)=2\sin\theta\cos\theta  

 sin2θ=1cos2θ\sin^2\theta=1-\cos^2\theta  

 cos2θ=1sin2θ\cos^2\theta=1-\sin^2\theta  

Tags

CCSS.HSF.TF.C.8

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

If you were given the equation 2cos2θ+3cosθ+1=02\cos^2\theta+3\cos\theta+1=0  and you likened it to the equation  2x2+3x+1=02x^2+3x+1=0  , what would its factored form be?

 (2x+3)(x+1)\left(2x+3\right)\left(x+1\right)  

 (2x+1)(x+1)\left(2x+1\right)\left(x+1\right)  

 (x+1)(x+1)\left(x+1\right)\left(x+1\right)  

 (3x+1)(x+1)\left(3x+1\right)\left(x+1\right)  

Tags

CCSS.HSA-REI.B.4B

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve equation for  0θ<2π0\le\theta<2\pi  .
 2+cotθ=3-2+\cot\theta=-3  

 θ=3π4,4π3,7π4\theta=\frac{3\pi}{4},\frac{4\pi}{3},\frac{7\pi}{4}  

 θ=3π4,7π4\theta=\frac{3\pi}{4},\frac{7\pi}{4}  

 θ=π3,4π3\theta=\frac{\pi}{3},\frac{4\pi}{3}  

 θ=3π4,4π3\theta=\frac{3\pi}{4},\frac{4\pi}{3}  

Tags

CCSS.HSF.TF.B.7

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve equation for  0θ<2π0\le\theta<2\pi  .
 4+csc2θ=2csc2θ4+\csc^2\theta=2\csc^2\theta  

 θ=5π6,4π3\theta=\frac{5\pi}{6},\frac{4\pi}{3}  

 θ=π6,5π6\theta=\frac{\pi}{6},\frac{5\pi}{6}  

 θ=π6,5π6,7π6,11π6\theta=\frac{\pi}{6},\frac{5\pi}{6},\frac{7\pi}{6},\frac{11\pi}{6}  

 θ=π6\theta=\frac{\pi}{6}  

Tags

CCSS.HSF.TF.B.7

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Solve equation for  0θ<2π0\le\theta<2\pi  .
 sinθcscθ+3cscθ=2sinθ+3cscθ-\sin\theta\csc\theta+3\csc\theta=\sqrt{2}\sin\theta+3\csc\theta  

 θ=5π4,11π6\theta=\frac{5\pi}{4},\frac{11\pi}{6}  

 θ=3π4,7π6,7π4\theta=\frac{3\pi}{4},\frac{7\pi}{6},\frac{7\pi}{4}  

 θ=0,π,5π4,7π4\theta=0,\pi,\frac{5\pi}{4},\frac{7\pi}{4}  

 θ=5π4,7π4\theta=\frac{5\pi}{4},\frac{7\pi}{4}  

Tags

CCSS.HSF.TF.B.7

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