quiz - completing the square for circles

quiz - completing the square for circles

8th - 10th Grade

16 Qs

quiz-placeholder

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quiz - completing the square for circles

quiz - completing the square for circles

Assessment

Quiz

Mathematics

8th - 10th Grade

Practice Problem

Medium

CCSS
HSG.GPE.A.1, HSA-REI.B.4B

Standards-aligned

Created by

Debra Leibowitz

Used 45+ times

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16 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does (h,k) standard for in the standard circle equation?

(h,k) is the center of the circle

(h,k) is a point on the circle.

(h,k) is a point that we guess and find

(h,k) is the distance of the circle

Tags

CCSS.HSG.GPE.A.1

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the r in the standard equation stand for?

r is the distance of the circle

r is the radius of the circle

r is the x coordinate of the center of the circle

r is the y coordinate of the center of the circle

Tags

CCSS.HSG.GPE.A.1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the coordinates of the center and the radius of the circle with equation:
(x - 4)2 + (y - 3)2 = 25 ?

Center (4,3)
Radius = 5 units
Center (4,3)
Radius = 25 units
Center (-4,-3)
Radius = 25 units
Center (-4,-3)
Radius = 5 units

Tags

CCSS.HSG.GPE.A.1

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Write the equation of a circle with center (7, 0) with radius 3.

(x - 7)2 + y2 = 9
x2 + (y -7)2 = 9
(x - 7)2 + y2 = 3
x2 + (y -7)2 = 3

Tags

CCSS.HSG.GPE.A.1

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A circle has the equation  x2 + y2 - 12x + 8y + 3 = 0.  Use completing the square to write the equation in standard form.

(x - 6)2 + (y + 4)2 = 49
(x + 4)2 + (y - 6)2 = 49
(x - 6)2 + (y + 4)2 = 55
x2 + y2 = 55

Tags

CCSS.HSG.GPE.A.1

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Change the following equation to standard form

x2 + y2- 4x +12y - 8 = 0

(x+2)2+(y-6)2=48

(x-2)2+(y+6)2=48

(x-6)2+(y-2)2=48

(x+2)2+(y-6)2=48

Tags

CCSS.HSG.GPE.A.1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the center and radius of the circle: x2 + y2 + 14x - 2y = -1

center= (-7,2) radius= 3

center= (-7,1) radius= 7

center= (-4,1) radius= 5

center = (7, -1) radius = 7

Tags

CCSS.HSG.GPE.A.1

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