E v a l u a t e sin ⁡ ( 270 − θ ) Evaluate\ \sin\left(270-\theta\right) E v a l u a t e sin ( 2 7 0 − θ )

− cos ⁡ θ -\cos\ \theta − cos θ

− sin ⁡ θ -\sin\theta − sin θ

tan ⁡ ( 90 + θ ) = \tan\left(90\ +\theta\right)= tan ( 9 0 + θ ) =

− cot ⁡ θ -\cot\theta − cot θ

− tan ⁡ θ -\tan\ \theta − tan θ

sec ⁡ ( 180 − θ ) = \sec\left(180-\theta\right)= sec ( 1 8 0 − θ ) =

− sec ⁡ θ -\sec\theta − sec θ

cosec ⁡ θ \operatorname{cosec}\ \theta c o s e c θ

− cosec ⁡ θ -\operatorname{cosec}\ \theta − c o s e c θ

cos ⁡ ( 180 + θ ) = \cos\left(180\ +\ \theta\right)=\ cos ( 1 8 0 + θ ) =

− cos ⁡ θ -\cos\ \theta − cos θ

− sin ⁡ θ -\ \sin\ \theta − sin θ

cot ⁡ ( 270 − θ ) = \cot\ \left(270-\theta\right)= cot ( 2 7 0 − θ ) =

− cot ⁡ θ -\ \cot\ \theta − cot θ

− tan ⁡ θ -\tan\ \theta − tan θ

cot ⁡ ( − 24 0 o ) \cot\ \left(-\ 240^{o^{ }}\right) cot ( − 2 4 0 o )

− 1 3 -\frac{1}{\sqrt{3}} − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 3 -\sqrt{3} − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 3 \frac{1}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

cos ⁡ ( 31 5 o ) \cos\ \left(315^o\right) cos ( 3 1 5 o )

1 2 \frac{1}{\sqrt{2}} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

− 1 2 -\frac{1}{\sqrt{2}} − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

sec ⁡ ( − 21 0 o ) \sec\left(-210^o\right) sec ( − 2 1 0 o )

− 2 3 \frac{-2}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 \frac{2}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2

− 3 2 -\frac{\sqrt{3}}{2} − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

tan ⁡ ( 360 − θ ) = \tan\left(360-\theta\right)= tan ( 3 6 0 − θ ) =

− tan ⁡ θ -\tan\ \theta − tan θ

− cot ⁡ θ -\cot\ \theta − cot θ

sin ⁡ ( 270 + θ ) \sin\ \left(270\ +\ \theta\right) sin ( 2 7 0 + θ )

− cos ⁡ θ -\ \cos\ \theta − cos θ

− sin ⁡ θ -\sin\ \theta − sin θ

Trigonometric Functions

Quiz

•

Mathematics

•

11th Grade

•

Practice Problem

•

Hard

•

CCSS

HSF.TF.C.9, HSF.TF.A.2, HSF.TF.A.4

Standards-aligned

Sanjana Jaisinghani

Used 83+ times

FREE Resource

Tags

CCSS.HSF.TF.A.2

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Trigonometric Functions

10 questions

$Evaluate\ \sin\left(270-\theta\right)$

$\tan\left(90\ +\theta\right)=$

$\sec\left(180-\theta\right)=$

$\cos\left(180\ +\ \theta\right)=\$

$\cot\ \left(270-\theta\right)=$

$\cot\ \left(-\ 240^{o^{ }}\right)$

$\cos\ \left(315^o\right)$

$\sec\left(-210^o\right)$

$\tan\left(360-\theta\right)=$

$\sin\ \left(270\ +\ \theta\right)$

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Trigonometric Functions

10 questions

Evaluate sin⁡(270−θ)Evaluate\ \sin\left(270-\theta\right)Evaluate sin(270−θ)

tan⁡(90 +θ)=\tan\left(90\ +\theta\right)=tan(90 +θ)=

sec⁡(180−θ)=\sec\left(180-\theta\right)=sec(180−θ)=

cos⁡(180 + θ)= \cos\left(180\ +\ \theta\right)=\ cos(180 + θ)=

cot⁡ (270−θ)=\cot\ \left(270-\theta\right)=cot (270−θ)=

cot⁡ (− 240o)\cot\ \left(-\ 240^{o^{ }}\right)cot (− 240o)

cos⁡ (315o)\cos\ \left(315^o\right)cos (315o)

sec⁡(−210o)\sec\left(-210^o\right)sec(−210o)

tan⁡(360−θ)=\tan\left(360-\theta\right)=tan(360−θ)=

sin⁡ (270 + θ)\sin\ \left(270\ +\ \theta\right)sin (270 + θ)

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$Evaluate\ \sin\left(270-\theta\right)$

$\tan\left(90\ +\theta\right)=$

$\sec\left(180-\theta\right)=$

$\cos\left(180\ +\ \theta\right)=\$

$\cot\ \left(270-\theta\right)=$

$\cot\ \left(-\ 240^{o^{ }}\right)$

$\cos\ \left(315^o\right)$

$\sec\left(-210^o\right)$

$\tan\left(360-\theta\right)=$

$\sin\ \left(270\ +\ \theta\right)$