E v a l u a t e sin ⁡ ( 270 − θ ) Evaluate\ \sin\left(270-\theta\right) E v a l u a t e sin ( 2 7 0 − θ )

− cos ⁡ θ -\cos\ \theta − cos θ

− sin ⁡ θ -\sin\theta − sin θ

tan ⁡ ( 90 + θ ) = \tan\left(90\ +\theta\right)= tan ( 9 0 + θ ) =

− cot ⁡ θ -\cot\theta − cot θ

− tan ⁡ θ -\tan\ \theta − tan θ

sec ⁡ ( 180 − θ ) = \sec\left(180-\theta\right)= sec ( 1 8 0 − θ ) =

− sec ⁡ θ -\sec\theta − sec θ

cosec ⁡ θ \operatorname{cosec}\ \theta c o s e c θ

− cosec ⁡ θ -\operatorname{cosec}\ \theta − c o s e c θ

cos ⁡ ( 180 + θ ) = \cos\left(180\ +\ \theta\right)=\ cos ( 1 8 0 + θ ) =

− cos ⁡ θ -\cos\ \theta − cos θ

− sin ⁡ θ -\ \sin\ \theta − sin θ

cot ⁡ ( 270 − θ ) = \cot\ \left(270-\theta\right)= cot ( 2 7 0 − θ ) =

− cot ⁡ θ -\ \cot\ \theta − cot θ

− tan ⁡ θ -\tan\ \theta − tan θ

cot ⁡ ( − 24 0 o ) \cot\ \left(-\ 240^{o^{ }}\right) cot ( − 2 4 0 o )

− 1 3 -\frac{1}{\sqrt{3}} − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

− 3 -\sqrt{3} − 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 3 \frac{1}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

cos ⁡ ( 31 5 o ) \cos\ \left(315^o\right) cos ( 3 1 5 o )

1 2 \frac{1}{\sqrt{2}} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

− 1 2 -\frac{1}{\sqrt{2}} − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 1

sec ⁡ ( − 21 0 o ) \sec\left(-210^o\right) sec ( − 2 1 0 o )

− 2 3 \frac{-2}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2

3 2 \frac{\sqrt{3}}{2} 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 3 \frac{2}{\sqrt{3}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 2

− 3 2 -\frac{\sqrt{3}}{2} − 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

tan ⁡ ( 360 − θ ) = \tan\left(360-\theta\right)= tan ( 3 6 0 − θ ) =

− tan ⁡ θ -\tan\ \theta − tan θ

− cot ⁡ θ -\cot\ \theta − cot θ

sin ⁡ ( 270 + θ ) \sin\ \left(270\ +\ \theta\right) sin ( 2 7 0 + θ )

− cos ⁡ θ -\ \cos\ \theta − cos θ

− sin ⁡ θ -\sin\ \theta − sin θ

Trigonometric Functions

Authored by Sanjana Jaisinghani

Mathematics

11th Grade

CCSS covered

Used 83+ times

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

Content View

Student View

10 questions

Show all answers

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$Evaluate\ \sin\left(270-\theta\right)$

$\sin\theta$

$-\cos\ \theta$

$-\sin\theta$

$\cos\theta$

Tags

CCSS.HSF.TF.C.9

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\tan\left(90\ +\theta\right)=$

$-\cot\theta$

$\cot\theta$

$\tan\ \theta$

$-\tan\ \theta$

Tags

CCSS.HSF.TF.A.4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sec\left(180-\theta\right)=$

$\operatorname{cosec}\ \theta$

$\sec\ \theta$

$-\sec\theta$

$-\operatorname{cosec}\ \theta$

Tags

CCSS.HSF.TF.C.9

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\left(180\ +\ \theta\right)=\$

$\cos\ \theta$

$-\ \sin\ \theta$

$\sin\ \theta$

$-\cos\ \theta$

Tags

CCSS.HSF.TF.C.9

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cot\ \left(270-\theta\right)=$

$\tan\ \theta$

$-\ \cot\ \theta$

$-\tan\ \theta$

$\cot\ \theta$

Tags

CCSS.HSF.TF.C.9

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cot\ \left(-\ 240^{o^{ }}\right)$

$\sqrt{3}$

$-\frac{1}{\sqrt{3}}$

$-\sqrt{3}$

$\frac{1}{\sqrt{3}}$

Tags

CCSS.HSF.TF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\cos\ \left(315^o\right)$

$-\frac{1}{\sqrt{2}}$

$\frac{1}{2}$

$\frac{1}{\sqrt{2}}$

$-\frac{1}{2}$

Tags

CCSS.HSF.TF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sec\left(-210^o\right)$

$\frac{\sqrt{3}}{2}$

$\frac{2}{\sqrt{3}}$

$-\frac{\sqrt{3}}{2}$

$\frac{-2}{\sqrt{3}}$

Tags

CCSS.HSF.TF.A.2

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\tan\left(360-\theta\right)=$

$\cot\ \theta$

$\tan\ \theta$

$-\tan\ \theta$

$-\cot\ \theta$

Tags

CCSS.HSF.TF.C.9

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\sin\ \left(270\ +\ \theta\right)$

$\sin\ \theta$

$-\ \cos\ \theta$

$-\sin\ \theta$

$\cos\ \theta$

Tags

CCSS.HSF.TF.C.9

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

13 questions

показникова і логарифмічна функції

Quiz

•

11th Grade

10 questions

persamaan trigonometri sederhana1

Quiz

•

11th Grade

15 questions

Calculo Integral (1er Parcial)

Quiz

•

11th - 12th Grade

12 questions

Translating Sine & Cosine Functions

Quiz

•

9th - 12th Grade

15 questions

XIV Olimpiadas de Matemáticas - 11mo

Quiz

•

11th Grade

10 questions

RUMUS TRIGONOMETRI 1

Quiz

•

11th Grade

10 questions

การประยุกต์ตรีโกณมิติ

Quiz

•

11th Grade - Professi...

12 questions

MFM2P Trigonometry - finding side length

Quiz

•

10th - 12th Grade

Popular Resources on Wayground

15 questions

Fractions on a Number Line

Quiz

•

3rd Grade

20 questions

Equivalent Fractions

Quiz

•

3rd Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

54 questions

Analyzing Line Graphs & Tables

Quiz

•

4th Grade

$fractions$

22 questions

fractions

Quiz

•

3rd Grade

20 questions

Main Idea and Details

Quiz

•

5th Grade

20 questions

Context Clues

Quiz

•

6th Grade

15 questions

Equivalent Fractions

Quiz

•

4th Grade

Discover more resources for Mathematics

12 questions

Add and Subtract Polynomials

Quiz

•

9th - 12th Grade

15 questions

Exponential Growth and Decay Word Problems Practice

Quiz

•

9th - 12th Grade

20 questions

Classifying Polynomials by Degree and Number of Terms

Quiz

•

11th Grade

17 questions

Explore Experimental and Theoretical Probability

Quiz

•

7th - 12th Grade

15 questions

Parallelogram Properties

Quiz

•

10th - 12th Grade

10 questions

Special Right Triangles

Quiz

•

11th Grade

18 questions

Solving Systems- Word Problems

Quiz

•

9th - 12th Grade

34 questions

7.4 Review Cubic and Cube Root Functions

Quiz

•

10th - 12th Grade

Trigonometric Functions

Evaluate sin⁡(270−θ)Evaluate\ \sin\left(270-\theta\right)Evaluate sin(270−θ)

tan⁡(90 +θ)=\tan\left(90\ +\theta\right)=tan(90 +θ)=

sec⁡(180−θ)=\sec\left(180-\theta\right)=sec(180−θ)=

cos⁡(180 + θ)= \cos\left(180\ +\ \theta\right)=\ cos(180 + θ)=

cot⁡ (270−θ)=\cot\ \left(270-\theta\right)=cot (270−θ)=

cot⁡ (− 240o)\cot\ \left(-\ 240^{o^{ }}\right)cot (− 240o)

cos⁡ (315o)\cos\ \left(315^o\right)cos (315o)

sec⁡(−210o)\sec\left(-210^o\right)sec(−210o)

tan⁡(360−θ)=\tan\left(360-\theta\right)=tan(360−θ)=

sin⁡ (270 + θ)\sin\ \left(270\ +\ \theta\right)sin (270 + θ)

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

$Evaluate\ \sin\left(270-\theta\right)$

$\tan\left(90\ +\theta\right)=$

$\sec\left(180-\theta\right)=$

$\cos\left(180\ +\ \theta\right)=\$

$\cot\ \left(270-\theta\right)=$

$\cot\ \left(-\ 240^{o^{ }}\right)$

$\cos\ \left(315^o\right)$

$\sec\left(-210^o\right)$

$\tan\left(360-\theta\right)=$

$\sin\ \left(270\ +\ \theta\right)$