BC Calculus - Series Assessment

BC Calculus - Series Assessment

10th - 12th Grade

10 Qs

quiz-placeholder

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BC Calculus - Series Assessment

BC Calculus - Series Assessment

Assessment

Quiz

Mathematics

10th - 12th Grade

Medium

CCSS
RI.11-12.10, RI.7.10, RI.8.10

+2

Standards-aligned

Created by

Daniel Southard

Used 67+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Determine whether the series is absolutely convergent, conditionally convergent, or divergent.

 n=1n22n\sum_{n=1}^{\infty}\frac{n^2}{2^n}  

Absolutely Convergent

Conditionally Convergent

Divergent

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Determine whether the series is absolutely convergent, conditionally convergent, or divergent.

 n=1n21n2+1\sum_{n=1}^{\infty}\frac{n^2-1}{n^2+1}  

Absolutely Convergent

Conditionally Convergent

Divergent

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Determine whether the series is absolutely convergent, conditionally convergent, or divergent.

 n=1(1)n12nn4\sum_{n=1}^{\infty}\left(-1\right)^{n-1}\frac{2^n}{n^4}  

Absolutely Convergent

Conditionally Convergent

Divergent

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Determine whether the series is absolutely convergent, conditionally convergent, or divergent.

 n=1(1)n+1n\sum_{n=1}^{\infty}\frac{\left(-1\right)^{n+1}}{\sqrt{n}}  

Absolutely Convergent

Conditionally Convergent

Divergent

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Determine whether the series is absolutely convergent, conditionally convergent, or divergent.

 n=1n2+1n3+1\sum_{n=1}^{\infty}\frac{n^2+1}{n^3+1}  

Absolutely Convergent

Conditionally Convergent

Divergent

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the Radius of Convergence for;

 n=0xnn\sum_{n=0}^{\infty}\frac{x^n}{\sqrt{n}} 


 R=0R=0  

 R=12R=\frac{1}{2}  

 R=1R=1  

 R=R=\infty  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which of the following is the first 3 terms for the Maclaurin Series of;

 f(x)=sin(x)f\left(x\right)=\sin\left(x\right)  


 1+x+x221+x+\frac{x^2}{2}  

 1x22!+x44!1-\frac{x^2}{2!}+\frac{x^4}{4!}  

 xx33!+x55!x-\frac{x^3}{3!}+\frac{x^5}{5!}  

 1+x+x21+x+x^2  

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