Inverse Trigonometry Class XII

Inverse Trigonometry Class XII

12th Grade

10 Qs

quiz-placeholder

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Inverse Trigonometry Class XII

Inverse Trigonometry Class XII

Assessment

Quiz

Mathematics

12th Grade

Practice Problem

Hard

CCSS
HSF.TF.B.7, HSF.TF.C.8, HSF.TF.C.9

+1

Standards-aligned

Created by

Nilesh gulati

Used 267+ times

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

 tan13sec1(2)=\tan^{-1}\sqrt{3}-\sec^{-1}\left(-2\right)=  

 π\pi  

 π3-\frac{\pi}{3}  

 π3\frac{\pi}{3}  

 2π3\frac{2\pi}{3}  

Tags

CCSS.HSF.TF.B.7

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 tan1(xy)tan1(xyx+y)=\tan^{-1}\left(\frac{x}{y}\right)-\tan^{-1}\left(\frac{x-y}{x+y}\right)=  

 π2\frac{\pi}{2}  

 π3\frac{\pi}{3}  

 π4\frac{\pi}{4}  

 3π4\frac{3\pi}{4}  

Tags

CCSS.HSF.TF.C.9

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 sin1[cos(sin1(32))]=\sin^{-1}\left[\cos\left(\sin^{-1}\left(\frac{\sqrt{3}}{2}\right)\right)\right]=  

 π6\frac{\pi}{6}  

 π3\frac{\pi}{3}  

 π4\frac{\pi}{4}  

 π2\frac{\pi}{2}  

Tags

CCSS.HSF.TF.B.7

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The principal value branch of  sec1x\sec^{-1}x  is

 [π2,π2]{0}\left[-\frac{\pi}{2},\frac{\pi}{2}\right]-\left\{0\right\}  

 [0,π]{π2}\left[0,\pi\right]-\left\{\frac{\pi}{2}\right\}  

 (0, π)\left(0,\ \pi\right)  

 (π2, π2)\left(-\frac{\pi}{2},\ \frac{\pi}{2}\right)  

Tags

CCSS.HSF-BF.B.4D

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The value of  cot(sin1x)\cot\left(\sin^{-1}x\right)  is

 (1+x2)x\frac{\left(\sqrt{1+x^2}\right)}{x}  

 x1+x2\frac{x}{\sqrt{1+x^2}}  

 1x\frac{1}{x}  

 1x2x\frac{\sqrt{1-x^2}}{x}  

Tags

CCSS.HSF.TF.C.8

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If  tan1x=π10,\tan^{-1}x=\frac{\pi}{10},  then value of  cot1x\cot^{-1}x  is

 π5\frac{\pi}{5}  

 2π5\frac{2\pi}{5}  

 3π5\frac{3\pi}{5}  

 4π5\frac{4\pi}{5}  

Tags

CCSS.HSF.TF.B.7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The principal value of \sin^{-1}\left(-\frac{\sqrt{3}}{2}\right)  is

 2π3-\frac{2\pi}{3}  

 π3-\frac{\pi}{3}  

 4π3\frac{4\pi}{3}  

 5π3\frac{5\pi}{3}  

Tags

CCSS.HSF.TF.B.7

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