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Tes 1 Induksi Matematika Kelas XI SMAC

Authored by Rosalia Lumantari

Mathematics

11th Grade

CCSS covered

Used 62+ times

Tes 1 Induksi Matematika Kelas XI SMAC
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12 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Hasil dari  i=152i2 = ...\sum_{i=1}^52i^2\ =\ ...  

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2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Nilai  n=117( 3n  7 ) =...\sum_{n=1}^{17}\left(\ 3n\ -\ 7\ \right)\ =...  

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3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Berdasarkan prinsip Induksi Matematika, untuk membuktikan suatu pernyataan matematis P(n) dengan n merupakan anggota himpunan bilangan asli, maka langkah pertama harus dibuktikan bahwa .....

P(n) bernilai benar untuk n = 1.

P(n) bernilai benar untuk n = k.

P(n) bernilai benar untuk n = k+1.

P(n) bernilai benar untuk n = 0

P(n) bernilai benar untuk n = k - 1

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 13 + 23+33+43+...+1031^{3\ }+\ 2^3+3^3+4^3+...+10^3  dapat ditulis  sebagai ...

 n=05n3\sum_{n=0}^5n^3  

 n=110n3\sum_{n=1}^{10}n^3  

 n=1n103\sum_{n=1}^n10^3  

 n=1310n\sum_{n=1}^310^n  

 n=110(1 +n)3\sum_{n=1}^{10}\left(1\ +n\right)^3  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

3+5+7+...+15 = ...

n=16(2n1)\sum_{n=1}^6\left(2n-1\right)

n=17(2n1)\sum_{n=1}^7\left(2n-1\right)

n=18(2n1)\sum_{n=1}^8\left(2n-1\right)

n=17(2n+1)\sum_{n=1}^7\left(2n+1\right)

n=18(2n+1)\sum_{n=1}^8\left(2n+1\right)

Tags

CCSS.6.EE.A.2

CCSS.6.EE.A.3

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Notasi sigma dari penjumlahan

2 . 7 + 3 . 9 + 4 . 11 + 5 . 13 yaitu ....

n=14(n+1)(2n+5)\sum_{n=1}^4\left(n+1\right)\left(2n+5\right)

n=15(n+1)(2n+5)\sum_{n=1}^5\left(n+1\right)\left(2n+5\right)

n=16(n+1)(2n+5)\sum_{n=1}^6\left(n+1\right)\left(2n+5\right)

n=14(n+1)(2n+7)\sum_{n=1}^4\left(n+1\right)\left(2n+7\right)

n=15(n+1)(2n+7)\sum_{n=1}^5\left(n+1\right)\left(2n+7\right)

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Nilai dari  n=15n (n+1)(n+2)3=....\sum_{n=1}^5\frac{\text{n (n+1)(n+2)}}{3}=....  

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