UH LIMIT

Authored by Abdul Ma'ruf

Mathematics

12th Grade

Used 48+ times

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15 questions

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MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow-2}\ \left(\frac{3x^2+5x-2}{x^2+x-2}\right)=....$

$-2\frac{2}{3}$

$-2\frac{1}{3}$

$2\frac{1}{3}$

$2\frac{2}{3}$

$3\frac{2}{3}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow3}\ \left(\frac{x^2-2x-3}{x^2-7x+12}\right)=....$

-4

-3

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow0}\ \ \left(\frac{3x^2-4x}{x}\right)=....$

-4

-1

$\frac{4}{3}$

$\infty$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow\infty}\ \ \left(\frac{5x^2+6x+2}{4x^2+2x+1}\right)=....$

$1\frac{1}{4}$

$\infty$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow\infty}\ \left(\frac{6x^2-3x-4}{3-x^2}\right)=....$

-1

-6

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai
$\lim_{x\rightarrow3}\ \ \left(\frac{2x^2-11x+15}{x^2-9}\right)=....$

$\frac{1}{6}$

$\frac{1}{3}$

$\frac{5}{6}$

$\frac{11}{6}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow\infty}\ \left(2x+1\right)-\sqrt{4x^2+2x-2}$ adalah ....

$-\frac{7}{2}$

$-\frac{5}{3}$

$\frac{1}{4}$

$\frac{1}{3}$

$\frac{1}{2}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow2}\ \left(\frac{4-x^2}{3-\sqrt{x^2+5}}\right)=....$

-12

-6

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow6}\ \ \left(\frac{\sqrt{3x-2}-\sqrt{2x+4}}{x-6}\right)=....$

$-\frac{1}{4}$

$-\frac{1}{8}$

$\frac{1}{8}$

$\frac{1}{4}$

10.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Nilai dari
$\lim_{x\rightarrow3}\ \ \left(\frac{x^2-x-6}{4-\sqrt{5x+1}}\right)=....$

-8

-6

$\infty$

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UH LIMIT

Nilai dari lim⁡x→−2 (3x2+5x−2x2+x−2)=....\lim_{x\rightarrow-2}\ \left(\frac{3x^2+5x-2}{x^2+x-2}\right)=....x→−2lim​ (x2+x−23x2+5x−2​)=....

Nilai dari lim⁡x→3 (x2−2x−3x2−7x+12)=....\lim_{x\rightarrow3}\ \left(\frac{x^2-2x-3}{x^2-7x+12}\right)=....x→3lim​ (x2−7x+12x2−2x−3​)=....

Nilai dari lim⁡x→0 (3x2−4xx)=....\lim_{x\rightarrow0}\ \ \left(\frac{3x^2-4x}{x}\right)=....x→0lim​ (x3x2−4x​)=....

Nilai dari lim⁡x→∞ (5x2+6x+24x2+2x+1)=....\lim_{x\rightarrow\infty}\ \ \left(\frac{5x^2+6x+2}{4x^2+2x+1}\right)=....x→∞lim​ (4x2+2x+15x2+6x+2​)=....

Nilai dari lim⁡x→∞ (6x2−3x−43−x2)=....\lim_{x\rightarrow\infty}\ \left(\frac{6x^2-3x-4}{3-x^2}\right)=....x→∞lim​ (3−x26x2−3x−4​)=....

Nilai lim⁡x→3 (2x2−11x+15x2−9)=....\lim_{x\rightarrow3}\ \ \left(\frac{2x^2-11x+15}{x^2-9}\right)=....x→3lim​ (x2−92x2−11x+15​)=....

Nilai dari lim⁡x→∞ (2x+1)−4x2+2x−2\lim_{x\rightarrow\infty}\ \left(2x+1\right)-\sqrt{4x^2+2x-2}x→∞lim​ (2x+1)−4x2+2x−2​ adalah ....

Nilai dari lim⁡x→2 (4−x23−x2+5)=....\lim_{x\rightarrow2}\ \left(\frac{4-x^2}{3-\sqrt{x^2+5}}\right)=....x→2lim​ (3−x2+5​4−x2​)=....

Nilai dari lim⁡x→6 (3x−2−2x+4x−6)=....\lim_{x\rightarrow6}\ \ \left(\frac{\sqrt{3x-2}-\sqrt{2x+4}}{x-6}\right)=....x→6lim​ (x−63x−2​−2x+4​​)=....

Nilai dari lim⁡x→3 (x2−x−64−5x+1)=....\lim_{x\rightarrow3}\ \ \left(\frac{x^2-x-6}{4-\sqrt{5x+1}}\right)=....x→3lim​ (4−5x+1​x2−x−6​)=....

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Nilai dari
$\lim_{x\rightarrow-2}\ \left(\frac{3x^2+5x-2}{x^2+x-2}\right)=....$

Nilai dari
$\lim_{x\rightarrow3}\ \left(\frac{x^2-2x-3}{x^2-7x+12}\right)=....$

Nilai dari
$\lim_{x\rightarrow0}\ \ \left(\frac{3x^2-4x}{x}\right)=....$

Nilai dari
$\lim_{x\rightarrow\infty}\ \ \left(\frac{5x^2+6x+2}{4x^2+2x+1}\right)=....$

Nilai dari
$\lim_{x\rightarrow\infty}\ \left(\frac{6x^2-3x-4}{3-x^2}\right)=....$

Nilai
$\lim_{x\rightarrow3}\ \ \left(\frac{2x^2-11x+15}{x^2-9}\right)=....$

Nilai dari
$\lim_{x\rightarrow\infty}\ \left(2x+1\right)-\sqrt{4x^2+2x-2}$ adalah ....

Nilai dari
$\lim_{x\rightarrow2}\ \left(\frac{4-x^2}{3-\sqrt{x^2+5}}\right)=....$

Nilai dari
$\lim_{x\rightarrow6}\ \ \left(\frac{\sqrt{3x-2}-\sqrt{2x+4}}{x-6}\right)=....$

Nilai dari
$\lim_{x\rightarrow3}\ \ \left(\frac{x^2-x-6}{4-\sqrt{5x+1}}\right)=....$