lim ⁡ x → 1 4 π cos ⁡ 2 x cos ⁡ x − sin ⁡ x = \lim_{x\rightarrow\ \frac{1}{4}\pi}\ \frac{\cos\ 2x}{\cos\ x\ -\ \sin\ x}= x → 4 1 π lim cos x − sin x cos 2 x =

2 \sqrt{2} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 2 \frac{1}{2}\ \sqrt{2} 2 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 4 2 \frac{1}{4}\ \sqrt{2} 4 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

lim ⁡ x → ∞ ( ( 2 x ) ( x − 1 ) − x ( x + 3 ) ) \lim_{x\rightarrow\infty}\ \left(\sqrt{\left(2x\right)\left(x-1\right)}-\sqrt{x\left(x+3\right)}\right) x → ∞ lim ( ( 2 x ) ( x − 1 ) <path d="M263,681c0.7,0,18,39.7,52,119c34,79.3,68.167, 158.7,102.5,238c34.3,79.3,51.8,119.3,52.5,120c340,-704.7,510.7,-1060.3,512,-1067 c4.7,-7.3,11,-11,19,-11H40000v40H1012.3s-271.3,567,-271.3,567c-38.7,80.7,-84, 175,-136,283c-52,108,-89.167,185.3,-111.5,232c-22.3,46.7,-33.8,70.3,-34.5,71 c-4.7,4.7,-12.3,7,-23,7s-12,-1,-12,-1s-109,-253,-109,-253c-72.7,-168,-109.3, -252,-110,-252c-10.7,8,-22,16.7,-34,26c-22,17.3,-33.3,26,-34,26s-26,-26,-26,-26 s76,-59,76,-59s76,-60,76,-60z M1001 80H40000v40H1012z"> − x ( x + 3 ) <path d="M263,681c0.7,0,18,39.7,52,119c34,79.3,68.167, 158.7,102.5,238c34.3,79.3,51.8,119.3,52.5,120c340,-704.7,510.7,-1060.3,512,-1067 c4.7,-7.3,11,-11,19,-11H40000v40H1012.3s-271.3,567,-271.3,567c-38.7,80.7,-84, 175,-136,283c-52,108,-89.167,185.3,-111.5,232c-22.3,46.7,-33.8,70.3,-34.5,71 c-4.7,4.7,-12.3,7,-23,7s-12,-1,-12,-1s-109,-253,-109,-253c-72.7,-168,-109.3, -252,-110,-252c-10.7,8,-22,16.7,-34,26c-22,17.3,-33.3,26,-34,26s-26,-26,-26,-26 s76,-59,76,-59s76,-60,76,-60z M1001 80H40000v40H1012z"> ) = ...

− 5 2 2 -\frac{5}{2}\sqrt{2} − 2 5 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 4 2 \frac{1}{4}\sqrt{2} 4 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 2 \frac{1}{2}\sqrt{2} 2 1 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Nilai dari lim ⁡ x → π 12 tan ⁡ 2 x tan ⁡ 3 x \lim_{x\rightarrow\frac{\pi}{12}}\frac{\tan\ 2x}{\tan\ 3x} x → 1 2 π lim tan 3 x tan 2 x adalah ...

1 3 3 \frac{1}{3}\sqrt{3} 3 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 \sqrt{3} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

1 2 3 \frac{1}{2}\sqrt{3} 2 1 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

lim ⁡ x → π 4 cos ⁡ 2 x cos ⁡ x − sin ⁡ x = . . . \lim_{x\rightarrow\ \frac{\pi}{4}}\ \frac{\cos\ 2x}{\cos\ x\ -\sin\ x}=... x → 4 π lim cos x − sin x cos 2 x = . . .

2 \sqrt{2} 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Bank Soal Limit Fungsi

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Bank Soal Limit Fungsi

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12th Grade

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Practice Problem

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Hard

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CCSS

HSF.TF.A.2, HSA.APR.D.6, HSA.SSE.B.3

Standards-aligned

mutia irawan

Used 1+ times

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50 questions

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\lim_{x\rightarrow0}\ \frac{2x}{\cos\ x}$

$\infty$

tidak ada

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\lim_{x\rightarrow0}\ \frac{Sin\ 2x\ .\ Tan\ 3x}{4x^2}$

$\frac{3}{2}$

$\frac{3}{4}$

$\frac{3}{8}$

$\frac{1}{4}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\lim_{x\rightarrow0}\ \frac{1-\cos^2\ 2x}{3x.\ \tan\ 2x}$

$\frac{2}{3}$

$\frac{1}{3}$

$\frac{1}{6}$

$-\frac{2}{3}$

$-\frac{1}{3}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\lim_{x\rightarrow0}\ \frac{\sin\ 3x\ +\ \tan\ 4x}{5x}$

$\frac{1}{5}$

$-\frac{1}{5}$

$\frac{7}{5}$

$-\frac{7}{5}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\lim_{x\rightarrow0}\ \frac{1-\cos\ 4x}{\left(3x\right)^2}=$

$\frac{8}{9}$

$\frac{7}{9}$

$\frac{6}{9}$

$\frac{3}{9}$

$\frac{1}{9}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\lim_{x\rightarrow\ \frac{1}{4}\pi}\ \frac{\cos\ 2x}{\cos\ x\ -\ \sin\ x}=$

$\sqrt{2}$

$\frac{1}{2}\ \sqrt{2}$

$\frac{1}{4}\ \sqrt{2}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\lim_{x\rightarrow2}\ \frac{\sin\left(x-2\right)}{2x-4}=$

$\frac{1}{2}$

$\frac{1}{4}$

$\sim$

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Bank Soal Limit Fungsi

50 questions

$\lim_{x\rightarrow0}\ \frac{2x}{\cos\ x}$

$\lim_{x\rightarrow0}\ \frac{Sin\ 2x\ .\ Tan\ 3x}{4x^2}$

$\lim_{x\rightarrow0}\ \frac{1-\cos^2\ 2x}{3x.\ \tan\ 2x}$

$\lim_{x\rightarrow0}\ \frac{\sin\ 3x\ +\ \tan\ 4x}{5x}$

$\lim_{x\rightarrow0}\ \frac{1-\cos\ 4x}{\left(3x\right)^2}=$

$\lim_{x\rightarrow\ \frac{1}{4}\pi}\ \frac{\cos\ 2x}{\cos\ x\ -\ \sin\ x}=$

$\lim_{x\rightarrow2}\ \frac{\sin\left(x-2\right)}{2x-4}=$

$\lim_{x\rightarrow3}\ \frac{Sin\left(2x-6\right)}{x^2\ -9}=$

$\lim_{x\rightarrow0\ }\ \frac{\cos\ 5x\ -\cos\ 3x}{x.\ \sin\ 2x}=$

$\lim_{x\rightarrow\infty}\ \frac{2x+6}{x-6}=...$

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Bank Soal Limit Fungsi

50 questions

lim⁡x→0 2xcos⁡ x\lim_{x\rightarrow0}\ \frac{2x}{\cos\ x}x→0lim​ cos x2x​

lim⁡x→0 Sin 2x . Tan 3x4x2\lim_{x\rightarrow0}\ \frac{Sin\ 2x\ .\ Tan\ 3x}{4x^2}x→0lim​ 4x2Sin 2x . Tan 3x​

lim⁡x→0 1−cos⁡2 2x3x. tan⁡ 2x\lim_{x\rightarrow0}\ \frac{1-\cos^2\ 2x}{3x.\ \tan\ 2x}x→0lim​ 3x. tan 2x1−cos2 2x​

lim⁡x→0 sin⁡ 3x + tan⁡ 4x5x\lim_{x\rightarrow0}\ \frac{\sin\ 3x\ +\ \tan\ 4x}{5x}x→0lim​ 5xsin 3x + tan 4x​

lim⁡x→0 1−cos⁡ 4x(3x)2=\lim_{x\rightarrow0}\ \frac{1-\cos\ 4x}{\left(3x\right)^2}=x→0lim​ (3x)21−cos 4x​=

lim⁡x→ 14π cos⁡ 2xcos⁡ x − sin⁡ x=\lim_{x\rightarrow\ \frac{1}{4}\pi}\ \frac{\cos\ 2x}{\cos\ x\ -\ \sin\ x}=x→ 41​πlim​ cos x − sin xcos 2x​=

lim⁡x→2 sin⁡(x−2)2x−4=\lim_{x\rightarrow2}\ \frac{\sin\left(x-2\right)}{2x-4}=x→2lim​ 2x−4sin(x−2)​=

lim⁡x→3 Sin(2x−6)x2 −9=\lim_{x\rightarrow3}\ \frac{Sin\left(2x-6\right)}{x^2\ -9}=x→3lim​ x2 −9Sin(2x−6)​=

lim⁡x→0 cos⁡ 5x −cos⁡ 3xx. sin⁡ 2x=\lim_{x\rightarrow0\ }\ \frac{\cos\ 5x\ -\cos\ 3x}{x.\ \sin\ 2x}=x→0 lim​ x. sin 2xcos 5x −cos 3x​=

lim⁡x→∞ 2x+6x−6=...\lim_{x\rightarrow\infty}\ \frac{2x+6}{x-6}=...x→∞lim​ x−62x+6​=...

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Discover more resources for Mathematics

$\lim_{x\rightarrow0}\ \frac{2x}{\cos\ x}$

$\lim_{x\rightarrow0}\ \frac{Sin\ 2x\ .\ Tan\ 3x}{4x^2}$

$\lim_{x\rightarrow0}\ \frac{1-\cos^2\ 2x}{3x.\ \tan\ 2x}$

$\lim_{x\rightarrow0}\ \frac{\sin\ 3x\ +\ \tan\ 4x}{5x}$

$\lim_{x\rightarrow0}\ \frac{1-\cos\ 4x}{\left(3x\right)^2}=$

$\lim_{x\rightarrow\ \frac{1}{4}\pi}\ \frac{\cos\ 2x}{\cos\ x\ -\ \sin\ x}=$

$\lim_{x\rightarrow2}\ \frac{\sin\left(x-2\right)}{2x-4}=$

$\lim_{x\rightarrow3}\ \frac{Sin\left(2x-6\right)}{x^2\ -9}=$

$\lim_{x\rightarrow0\ }\ \frac{\cos\ 5x\ -\cos\ 3x}{x.\ \sin\ 2x}=$

$\lim_{x\rightarrow\infty}\ \frac{2x+6}{x-6}=...$