Trigo for 3N

Trigo for 3N

8th Grade

9 Qs

quiz-placeholder

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Trigo for 3N

Trigo for 3N

Assessment

Quiz

Mathematics

8th Grade

Practice Problem

Medium

CCSS
HSG.SRT.D.10, HSF.TF.C.8, HSF.TF.C.9

+2

Standards-aligned

Created by

Wan Lo

Used 3+ times

FREE Resource

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9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

sin 40o=

sin140o

-sin140o

cos40o

sin-140o

Tags

CCSS.HSF.TF.C.8

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

cos60o=

cos120o

sin60o

-cos120o

cos-120o

Tags

CCSS.HSF.TF.C.8

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

cos130o=

a) - cos 50o

b) cos 50o

c) a negative answer

d) sin 50o

a only

a and b

a and c

a, c and d

Tags

CCSS.HSF.TF.C.9

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find an obtuse angle x if sin x = 0.6

36.9o

53.1o

143.1o

36.9o and 143.1o

Tags

CCSS.HSF.TF.B.7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What will you use to find angle DBC?

calculator

sine rule

cosine rule

TOA CAH SOH

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

6.

FILL IN THE BLANK QUESTION

1 min • 1 pt

Media Image

Find angle DBC, giving your answer correct to 3 significant figures.

You do not need to type the units.

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

How would you find the length of OM?

TOA CAH SOH

Sine rule

Cosine rule

Pythagoras Theorem

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

8.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which of the following statement/s is/are correct?

sinR7=sin426\frac{\sin R}{7}=\frac{\sin42}{6}

sin7R=sin642\frac{\sin7}{R}=\frac{\sin6}{42}

sinR6=sin427\frac{\sin R}{6}=\frac{\sin42}{7}

sinR42=sin76\frac{\sin R}{42}=\frac{\sin7}{6}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11

9.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Which statement(s) is/are correct?

OM2=82+822(8)(8)cos 45°OM^2=8^2+8^2-2\left(8\right)\left(8\right)\cos\ 45\degree

OMsin60=8sin45\frac{OM}{\sin60}=\frac{8}{\sin45}

OMsin45=8sin60\frac{OM}{\sin45}=\frac{8}{\sin60}

tan45°=OM8\tan45\degree=\frac{OM}{8}

Tags

CCSS.HSG.SRT.D.10

CCSS.HSG.SRT.D.11