Solving Eq's & Simple Quads HW

Which order of steps correctly solves the following equation for k?

 $24-k=16$  

• Add 24 to both sides, then divide both sides by -1.

• Add 24 to both sides, then add 1 to both sides.

• Subtract 24 from both sides, then divide both sides by -1.

• Subtract 24 from both sides, then add 1 to both sides. 

Tags

CCSS.6.EE.B.7

Solve for m:

 $-7m+9=m+1$  

(Only type a numerical answer. Ex: 9)

Solve for y:

 $2\left(y-4\right)=5\left(y-7\right)$  

(Only type a numerical answer. Ex: "2")

Tags

CCSS.8.EE.C.7B

Solve for x:

 $7x-8-3x=40$  

•  $\frac{24}{5}$  

• 12

• -12

•  $\frac{1}{12}$  

Tags

CCSS.7.EE.B.4A

Is this equation always, sometimes, or never true? Why?  $-6x+5=-6x-9$  

• always because -6x is on both sides of the equation

• sometimes bc both sides of the equation have -6x but  $5\ne-9$  

• never bc both sides of the equation have -6x but  $5\ne-9$  

Tags

CCSS.8.EE.C.7A

Solve for m: $\frac{4}{m}=\frac{2}{9}$  

(Only type a numerical answer. Ex: 2)

Tags

CCSS.6.EE.B.7

Which two steps will completely solve the equation for x: $8-\frac{x}{2}=-6$  

• 1. Subtract 8 from both sides

  2. Multiply both sides by -2
  

  
  

• 1. Subtract 8 from both sides

  2. Divide both sides by -2

• 1. Subtract 8  from both sides

  2. Multiply both sides by 2

• 1. Add 8 to both sides

  2. Multiply both sides by -2

Tags

CCSS.7.EE.B.4A

Solve for x: $6-2\left(3x-1\right)=5+3\left(2x+4\right)$  

•  $\frac{-21}{12}$  

• no solution

•  $\frac{-1}{3}$  

•  $\frac{-3}{4}$  

•  $\frac{-4}{3}$  

Select the two steps that will correctly solve the literal equation: $P=2L+2W;\ for\ W$  

• Step1: Divide both sides by 2

• Step1: Subtract 2L from both sides

• Step2: Divide both sides by 2

• Step2: Subtract 2L from both sides

• Step1: Add 2L to both sides

Tags

CCSS.HSA.CED.A.4

Check all the equations that are equivalent to: $y=\frac{C-Ax}{B}$  

•  $y=\frac{-Ax+C}{B}$  

•  $y=\frac{Ax-C}{B}$  

•  $y=\frac{-Ax}{B}+\frac{C}{B}$  

•  $y=\frac{Ax}{B}-\frac{C}{B}$  

•  $y=\frac{C}{B}-\frac{Ax}{B}$  

Tags

CCSS.HSA.CED.A.4