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Quadratic Transformations

Authored by Carrie Brown

Other, Mathematics

8th - 11th Grade

CCSS covered

Used 370+ times

Quadratic Transformations
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20 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the vertex?

 f(x)=(x4)2+3f\left(x\right)=\left(x-4\right)^2+3  

(-4,3)

(4,3)

(-4,-3)

(4,-3)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation would shift the following quadratic up 3 units?

 f(x)=(x4)2f\left(x\right)=\left(x-4\right)^2  

 f(x)=(x4)2+3f\left(x\right)=\left(x-4\right)^2+3  

 f(x)=(x4)23f\left(x\right)=\left(x-4\right)^2-3  

 f(x)=(x1)2f\left(x\right)=\left(x-1\right)^2  

 f(x)=(x7)2f\left(x\right)=\left(x-7\right)^2  

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the vertex?

 f(x)=(x+2)25f\left(x\right)=-\left(x+2\right)^2-5  

(-2,5)

(2,5)

(2,-5)

(-2,-5)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation would shift the quadratic equation right 3?

 f(x)=2(x+1)2+6f\left(x\right)=2\left(x+1\right)^2+6  

 f(x)=2(x3)2+6f\left(x\right)=2\left(x-3\right)^2+6  

 f(x)=2(x2)2+6f\left(x\right)=2\left(x-2\right)^2+6  

 f(x)=2(x+1)2+9f\left(x\right)=2\left(x+1\right)^2+9  

 f(x)=2(x+4)2+6f\left(x\right)=2\left(x+4\right)^2+6  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the new equation of the quadratic below that has a vertical shift of 4 units?

 f(x)=(x+2)25f\left(x\right)=-\left(x+2\right)^2-5  

 f(x)=(x+6)25f\left(x\right)=-\left(x+6\right)^2-5  

 f(x)=(x+2)21f\left(x\right)=-\left(x+2\right)^2-1  

 f(x)=4(x+2)25f\left(x\right)=-4\left(x+2\right)^2-5  

 f(x)=(x+2)2+4f\left(x\right)=-\left(x+2\right)^2+4  x = -5

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the vertex?

 f(x)=2(x+1)2+6f\left(x\right)=2\left(x+1\right)^2+6  

(-1, 6)

(2, 1)

(1, 6)

(6, -1)

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation would shift the quadratic function

 f(x)=x2f\left(x\right)=x^2  up 3 units and to the right 4 units.

 f(x)=(x+3)2+4f\left(x\right)=\left(x+3\right)^2+4  

 f(x)=3(x4)2f\left(x\right)=3\left(x-4\right)^2  

 f(x)=(x4)2+3f\left(x\right)=\left(x-4\right)^2+3  

 f(x)=(x+4)2+3f\left(x\right)=\left(x+4\right)^2+3  

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