Projectile Motion

Projectile motion is defined as the motion of an object that being projected and ____________________________.

• moves in space freely under the influence of gravity

• moves freely under the influence of constant velocity

• moves in space freely under the influence of force

• moves freely under the influence of constant acceleration

Tags

NGSS.HS-PS2-4

The vertical component of projectile motion moves with constant ______________________________.

• acceleration of -9.81 ms^-2

• velocity of -9.81 ms^-1

• acceleration of 0 ms^-2

• velocity of 0 ms^-1

The horizontal component of projectile motion moves with constant ______________________________.

• acceleration of -9.81 ms^-2

• velocity of -9.81 ms^-1

• acceleration of 0 ms^-2

• velocity of 0 ms^-1

Which of the following statements are TRUE about the conditions of an object at maximum height while undergoing projectile motion.

• the x-component for its velocity is equals to

  $u\ \sin\ \theta$

• the y-component for its velocity is equals to $0\ ms^{-1}$

• the magnitude of velocity is equals to the value of $u\ \sin\ \theta$

• the magnitude of velocity is $0\ ms^{-1}$

When an object reaches the highest point in projectile motion, the vertical component of its velocity will become __________________________________________________________.

• zero because the object will continue moving and falls to the ground

• non zero because the object will continue moving and falls to the ground

• zero because the object will stop for a short moment before it falls back to the ground

• non zero because the object will stop for a short moment before it falls back to the ground

At maximum height,  $v_y=0\ ms^{-1}\$  
If the vertical component is denoted as  $v_y$   and the maximum height is denoted as  $H$  . Which of the following equations may be used to calculate the value of  $H$  even if no time is provided in the question?

•  $v_{y_{\ }}=\ u_{y\ }-9.81t$  

•  $v_y^2=u_y^2-9.81H$  

•  $s_y=u_yt\ -\frac{1}{2}\left(9.81\right)t^2$  

How do we calculate the flight time for projectile motion?

• Find the time for the object to reach maximum height , then divide by 2

• Find the time for the object to reach maximum height , then multiply by 2

• Find the time for the object to reach maximum height , then add by 2

• Find the time for the object to reach maximum height , then subtract by 2

Horizontal range, R is the ...........

• maximum height

• maximum vertical displacement

• highest point

• maximum horizontal displacement

 $\theta=0^o$  

Projectile motion at this angle is also called as.....

• free fall

• horizontal projectile

• vertical projectile

 $u\ =10\ ms^{-1}$  

In horizontal projectile motion, if the value of its initial velocity is as above, what is the value of its x-component and y-component?

•  $u_x=0\ ms^{-1}\ ;\ u_y=10\ ms^{-1}$  

•  $u_x=10\ ms^{-1}\ ;\ u_y=10\ ms^{-1}$  

•  $u_x=10\ ms^{-1}\ ;\ u_y=0\ ms^{-1}$  

•  $u_x=0\ ms^{-1}\ ;\ u_y=0\ ms^{-1}$