Review solving linear equations and solutions of equations

Both shapes have the same perimeter. Solve for x.

• x = 12

• x = 17

• x = 32

• x = 22

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

CCSS.HSG.GPE.B.7

For the equation 3(2x - 5) = 6x + k, which value of k will create an equation with infinitely many solutions?

• 15

• -5

• 5

• -15

Tags

CCSS.HSA.REI.B.3

3(x + 5) = 2(3x + 12)

• 3

• -3

• 6

• -6

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

5(x -3) + 6 = 5x - 9

• one solution

• no solution

• infinitely many solutions

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

5(x -3) + 6 = 5x - 10

• one solution

• no solution

• infinitely many solutions

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

5(x -3) + 6 = 4x + 3

• one solution

• no solution

• infinitely many solutions

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

 $-\frac{3}{8}\left(-6-2y\right)=\frac{1}{2}\left(2y-3\right)-1$  

• y  = 19

• y = 6

• y = -1

• y = 15

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.A.2

CCSS.HSA.REI.B.3

3x - 8 = 10 - 3(x - 4)

• The solutions is x = 5

• The solution is approximately x = 4.67

• The solution is approximately x = -4.67

• There is no solution.

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Select a method that can be used to find the value x.

x - 18 = 6 - 3x

• Add x to both sides, subtract 6 from both sides, then divide both sides by 2.

• Add 3x to both sides add 18 to both sides, then divide both sides by 4.

• Subtract x from both sides, add 6 to both sides, then divide both sides by 4.

• Subtract 3x from both sides, subtract 18, then divide both sides by 2.

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Solve for x.

 $5.25x\ +\ 3.25\ =\ 1.75x\ +10.25$  

• x = -2

• x = 3

• x = -3

• x = 2

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3