Solve for h, S = 2 π r h 2\pi rh 2 π r h

h= S 2 π r \frac{S}{2\pi r} 2 π r S

h = S − 2 π r S-2\pi r S − 2 π r

h = 2 π r S \frac{2\pi r}{S} S 2 π r

Solve for x y = mx + b

x = y − b m x=\frac{y-b}{m} x = m y − b

x = y b m x=\frac{yb}{m} x = m y b

x = y + b m x=\frac{y+b}{m} x = m y + b

T = p + prt Solve for r

r = T − p p t r=\frac{T-p}{pt} r = p t T − p

r = T p − p t r=Tp-pt r = T p − p t

r = T p p t r=\frac{Tp}{pt} r = p t T p

r = T − p − p t r=T-p-pt r = T − p − p t

p = 2 l + 2 w p\ =\ 2l\ +\ 2w p = 2 l + 2 w solve for w

w = p − 2 l 2 w=\frac{p-2l}{2} w = 2 p − 2 l

w = p 2 l − 2 w=\frac{p}{2l}-2 w = 2 l p − 2

w = p + 2 l 2 w=\frac{p+2l}{2} w = 2 p + 2 l

w = 2 p − l w=2p-l w = 2 p − l

V = 1 3 B h V=\frac{1}{3}Bh V = 3 1 B h Solve for h

h = 3 V B h=\frac{3V}{B} h = B 3 V

h = 1 3 V − B h=\frac{1}{3}V-B h = 3 1 V − B

h = 1 3 V B h=\frac{\frac{1}{3}V}{B} h = B 3 1 V

h = 3 V − B h=3V-B h = 3 V − B

P = a + (n - 1)b Solve for b

b = P − a n − 1 b=\frac{P-a}{n-1} b = n − 1 P − a

b = P a + ( n − 1 ) b=\frac{P}{a+\left(n-1\right)} b = a + ( n − 1 ) P

b = P a − ( n − 1 ) b=\frac{P}{a}-\left(n-1\right) b = a P − ( n − 1 )

b = P n − 1 − a b=\frac{P}{n-1}-a b = n − 1 P − a

Solving Literal Equations

7th - 10th Grade

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24 Qs

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Solving Literal Equations

Quiz

•

Mathematics

•

7th - 10th Grade

•

Practice Problem

•

Medium

•

CCSS

HSA.CED.A.4, HSA.REI.B.3, 6.EE.C.9

Standards-aligned

Lisa Crosby

Used 21+ times

FREE Resource

24 questions

Show all answers

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for x:

x = yb - v

x = by - v

x = by + v

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

S = 3F - 24 Solve for F

F = (S + 24)/3

F = S/3 + 24

F = 3S + 24

F = 3(S + 24)

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

8x + 4y= 16 for y

y = -8x + 16

y = 2x -4

y = -2x + 4

y = -8x + 12

Tags

CCSS.6.EE.C.9

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for s:
2s = 6t + 8w

s = 12t + 16w

s = 6t + 4w

s = 3t - 4w

s = 3t + 4w

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve the literal equation for the given variable.

2A/h

2/(h)

2Ah

Ah/2

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve for w:
A = LW

A =^L/_W

w = ^L/_A

w = A

w = ^A/_L

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve:
C = 2πr, for r

C/(2π) = r

C + 2π = r

C - 2π = r

2πC = r

Tags

CCSS.HSA.CED.A.4

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Solving Literal Equations

24 questions

Solve for x:

S = 3F - 24 Solve for F

8x + 4y= 16 for y

Solve for s:
2s = 6t + 8w

Solve the literal equation for the given variable.

Solve for w:
A = LW

Solve:
C = 2πr, for r

d = rt, solve for r

Solve for T, B = T - Lc

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Solving Literal Equations

24 questions

Solve for x:

S = 3F - 24 Solve for F

8x + 4y= 16 for y

Solve for s:2s = 6t + 8w

Solve the literal equation for the given variable.

Solve for w:A = LW

Solve:C = 2πr, for r

d = rt, solve for r

Solve for T, B = T - Lc

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Solve for s:
2s = 6t + 8w

Solve for w:
A = LW

Solve:
C = 2πr, for r