Quiz 2-1 and 2-2

Body temperatures were collected from 130 individuals in degrees Celsius. The mean temp in Celsius was found to be 36.805 degrees. Use the fact that:   Degrees Fahrenheit = (9/5) times degrees Celsius + 32 to find the mean temperature in degrees Fahrenheit.

• 66.249 degrees Fahrenheit

• 98.249 degrees Fahrenheit

• 68.805 degrees Fahrenheit

• 36.805 degrees Fahrenheit

Tags

CCSS.HSA.CED.A.4

Body temperatures were collected from 130 individuals in degrees Celsius. The standard deviation of their temperatures in Celsius was found to be 0.408 degrees. Use the fact that: Degrees Fahrenheit = (9/5) times degrees Celsius + 32 to find the standard deviation of the temperatures in degrees Fahrenheit.

• 0.7344 degrees Fahrenheit

• 0.408 degrees Fahrenheit

• 32.7344 degrees Fahrenheit

• 32.408 degrees Fahrenheit

President Ronald Reagan lived to be 93 years old. If the mean lifespan is 71.45 years, and the standard deviation is 12.35 years calculate President Ronald Reagan's z-score.

• 0.64

• 1.13

• 1.74

• 7.53

Tags

CCSS.HSS.ID.A.4

A fire department in a rural county reports that its response time to fires is approximately normally distributed with a mean of 22 minutes and a standard deviation of 3.9 minutes.

a. What proportion of all response times for this fire department are below 18.5 minutes?

b. What proportion of all response times for this fire department are above 23.2 minutes?

c. Use the 68-95-99.7 rule to find the proportion of response times between 14.2 and 29.8 minutes.

Tags

CCSS.HSS.ID.A.4

A fire department in a rural county reports that its response time to fires is approximately normally distributed with a mean of 22 minutes and a standard deviation of 3.9 minutes.

A. What response time would 25% of the times recorded fall below?

B. What response time would 38% of the recorded times be above?

Tags

CCSS.HSS.ID.A.4

CCSS.HSS.MD.A.1