Unit 1 Assessment Review 9.16.20

10x + 9 = 4x - 9

• 0
• 3
• -3
• -18

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

8w - 8 = -4x + 16

• 8
• 16
• 24
• 2

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.A.2

12x - 15 = 3(2x+3)

• x = 4
• x = -4
• x = 2
• x = -2

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.A.2

Solve for x:

3 ( a + 22 ) = 12a + 30

• a = 8

• a = 2

• a = 4

• a = -2

Tags

CCSS.8.EE.C.7B

3x + 5 +2x = 12 + 4x

• x = 6
• x = 7
• x = 8
• x = 9

Check all steps that you would need to take to solve this equation:

 $4x-2=-2x+16$  

• Use distributive property to get rid of parentheses

• Combine like terms

• Move the variable to one side of the equation

• Use inverse operations to isolate and solve for the variable.

Solve:

 $3+12\left(3p+2\right)=9\left(p-3\right)$  

•  $p=-20$  

•  $p=-13$  

•  $p=-2$  

•  $p=-18$  

Solve: -2y + 8 = 4y - 10

• y = 3

• y = -3

• y = 6

• y = -6

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

• x = 5

• x = -45

• x = -5

• x = 4

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.A.2

 $5x+4=5x+4$  

• one solution

• no solution

• infinite solutions

Tags

CCSS.8.EE.C.7A