Solving Equations: Variable on both sides (2)

Solve: 4k + 39 = 7k + 6

• k = 11

• k = 3

• k = -3

• k = -11

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

Solve: 8b + 10 = 3b + 25

• b = -3

• b = 5

• b = 7

• b = 3

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

Find the solution to the following problem:

x+2=x+4

• all real numbers

• x=0

• no solution

• many solutions

Tags

CCSS.8.EE.C.7A

Is 7 a solution to the equation?

3x+8-x = 5x-4

• yes

• maybe

• no

Tags

CCSS.6.EE.B.5

Solve for x: 5(2x-1)=-5+10x

• x=5

• No solution

• x=0

• All real numbers

Tags

CCSS.8.EE.C.7A

Solve for x:

-6(2v + 4) = -8(v - 4)

• -8

• -13

• -14

• 14

Tags

CCSS.8.EE.C.7B

Solve for x:

-16 + 7n + n = 8n + 4n

• -4

• -14

• -16

• 11

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

 $3+5n=5\left(n+2\right)-7$  

• No Solution

• Infinitely Many Solutions

•  $n=-8$  

•  $n=-6$  

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.B.7

The steps in solving 5b - 6 = 24 are: 

• Add 6 to both sides and divide both sides by 5
• Add 6 to both sides and multiply both sides by 5
• Subtract 6 from both sides then multiply both sides by 5
• Subtract 6 from both sides then divide both sides by 5

Tags

CCSS.7.EE.B.4A

Find the error in the problem below
19 - 2k = 3k - 1
     +3k   +3k
19 + 1k = -1
-19           -19
k = -20

• They should have divided by 1 for the last step
• They should add 19 instead of subtracting 19
• I can not find an error
• Instead of adding 3k they should subtract 3k

Tags

CCSS.HSA.REI.A.1