2-1 Solving Systems using Substitution 09/28/2020

y = 2x + 9

x = -3

• (-3, -33)

• (-3, 8)

• (-3, 3)

• (3, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

6x = y

3y - 4x = 42

• (3, 18)

• (8, 2)

• (2, 8)

• (1, 6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = 2x - 4

7x - 2y = 5

• (-1, -6)

• (-1, -8)

• (-2, 6)

• (1, -8),

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve:
y=8x+1
y=6x+3

• (1, 9)
• (4, 14)
• (0, 1)
• (2, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Find the solution of the system of equations below using the substitution method:

y = 2x - 4

7x - 2y = 5

• (-1, -6)

• (-1, -8)

• (-2, 6)

• (1, -8),

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations.

• (-6, 1)

• (-12, -12)

• (1, -6)

• No solution

• Infinite solutions

Tags

CCSS.8.EE.C.8B

• No Solution

• (2, 2)

• (-1, 2)

• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = 2x - 1
4x + y = 17

• (5, 3)
• (3, 5)
• (2, 5)
• (5, 2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -2x + 5
y = 2x - 11

• No Solution
• (0, 0)
• (3, -1)
• (4, -3)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to this system?
2x + 3y = 4
y= 5x - 27

• (5,-2)
• (5, 2)
• (2,3)
• (3,2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6