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Chapter 2: Power, Polynomial, and Rational Functions

Authored by CJ Jung

Mathematics

9th - 12th Grade

CCSS covered

Used 34+ times

Chapter 2: Power, Polynomial, and Rational Functions
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20 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve the equation  (y4+2y6)14=y\left(y^4+2y-6\right)^{\frac{1}{4}}=y 

None is correct 

3

3, 9

-3

Tags

CCSS.HSA.REI.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve x=6x5x=\sqrt{6x-5}  


5

5, 1

5, 2

2

Tags

CCSS.HSA.REI.A.2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

 Graph f(x)=25x3Graph\ f\left(x\right)=\frac{2}{5}x^3  

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4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

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Use a graphing calculator to write a polynomial function to model the set of data.

0.9x - 1.3

1.3x - 0.9

0.9x + 1.3

1.3x + 0.9

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Graph f(x) = −2(x − 4)5 + 1

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6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Describe the end behavior of f(x) = −3x2 + 5x3 + 2x using limits. Explain your reasoning using the leading term test.

Because the degree is even and the leading coefficient is positive, limit of f(x) as x approaches -ve inf. equals +ve inf. and limit of f(x) as x approaches +ve inf. equals +ve inf.

Because the degree is odd and the leading coefficient is negative, limit of f(x) as x approaches -ve inf. equals +ve inf. and limit of f(x) as x approaches +ve inf. equals -ve inf.

Because the degree is odd and the leading coefficient is positive, limit of f(x) as x approaches -ve inf. equals -ve inf. and limit of f(x) as x approaches +ve inf. equals +ve inf.

Because the degree is even and the leading coefficient is negative, limit of f(x) as x approaches -ve inf. equals -ve inf. and limit of f(x) as x approaches +ve inf. equals -ve inf.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Use the Remainder Theorem to find the remainder for the division of

(x4 - 3x2 + 2x - 1) ÷ (x - 1). The remainder is ____.

2

1

0

-1

Tags

CCSS.HSA.APR.B.2

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