Solving Logarithms

You want to solve for x. Which of these is the correct "step 1"?

• $\log_78=\log_7x$

• $\log_742=\log_7x$

• $\log_748=\log_7\left(\frac{x}{6}\right)$

• $\log_754=\log_7x$

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

We want to solve for x. Which of these is the correct "step 1"?

• $\log\left(64\right)=\log\left(3x\right)$

• $\log\left(16\right)=\log\left(x^3\right)$

• $\log\left(16\right)=\log\left(3x\right)$

• $\log\left(64\right)=\log\left(x^3\right)$

• $\log\left(1\right)=\log\left(x^3\right)$

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

Which is the correct "step 1" to solve for x?
Hint: look at the schoology discussions if you feel stuck

•  $\log_2\left(100x^5\right)=7$  

•  $\log_2\left(95x\right)=7$  

•  $\log_2\left(20x\right)=7$  

•  $\log_2\left(500x\right)=7$  

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Solve for x.
 $\log_52+\log_5x=\log_520$  
x = _______

Tags

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

Solve for x.
 $2\log_410=\log_4\left(8x\right)+\log_4\left(5\right)$  

• x = 2.5

• x = 0.5

• x = 1.538

• x = 11.875

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

 $\log_4x^2=\log_43+\log_4\left(x+6\right)$  

Which quadratic equation would you wind up solving when solving the log equation?

•  $x^2-3x-18=0$  

•  $x^2+3x+6=0$  

•  $x^2-3x-6=0$  

•  $x^2-x-9=0$  

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

 $g\left(x\right)=-3\ln\left(x-4\right)-2$  
What is the asymptote of the function?

•  $x=-4$  

•  $y=2$  

•  $x=4$  

•  $y=-2$  

Tags

CCSS.HSF-IF.C.7E

Solve the equation.

• 0

• 2/3

• 3/2

• 1

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

Evaluate the following logarithm by solving for x:

log₈√8 = x

• x = -¹/₂

• x = -1

• x = 1

• ^{x = 1}/₂

Tags

CCSS.HSF.BF.B.5

Solve for x, as a simplified fraction:

• x = 6 / 5

• x = 25 / 6

• x = 6 / 25

• x = 5 / 6

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3