Operation with Whole Numbers

 $1465+793+21$  =

 $9718-5267\ =$  

 $9081\times7\ =$  

 $8238\div6=$  

One book costs $8.52. Calculate the cost of 6 books.

Subtract 89 from the sum of 247 and 193

• 35

• 78

• 351

• 204

 $\left(7+30\right)\times2-45=$  

• 29

• 22

• 18

• 0

 $382-792\div3=$  

• 264

• 118

• 665

• 136

 $2+3\times\left(3+2\right)=$  

• 13

• 25

• 4

• 17

How many times can 6 be taken away from 45?