Log Test Review

log₄(3x-1)=log₄(2x+3)

• 4

• 3

• 1

• 8

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.BF.B.5

log₅(4x-7)=log₅(x+5)

• 3
• 12
• 4
• 7

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.REI.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Solve:
log₉(x)+log₉(x+2)=log₉(35)

• 5
• -7
• 5, -7
• -7, -13

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

log₈(4x+4)=2

• 15

• 12

• 10

• 3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

Solve

• A
• B
• C
• D

Tags

CCSS.HSA.REI.A.1

CCSS.HSA.SSE.A.1

CCSS.HSA.SSE.B.3

Solve

• A
• B
• C
• D

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.LE.A.1

Solve:
log₄x² - log₄(x-1) = 1

• 4
• 3
• 2
• 1

Tags

CCSS.HSA.REI.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Sovle for x:
5^{-3x - 1} = 25

• x = -1
• x = -4
• x = -3
• x = 1

Tags

CCSS.HSA.CED.A.1

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

Are they inverses?

• No
• Yes

Tags

CCSS.HSF-BF.B.4B

Log with a base "e" (log_e) is the same thing as...

• "e"
• Natural Logarithm (LN)
• Common Logarithm (Log)
• Natural Log, base "e"
  LN_e

Tags

CCSS.HSF.BF.B.5