Hasil dari 125 − 1 3 180 + 45 − 20 \sqrt{125}-\frac{1}{3}\sqrt{180}+\sqrt{45}-\sqrt{20} 1 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 3 1 1 8 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> adalah...

4 5 4\sqrt{5} 4 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 5 5\sqrt{5} 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 5 3\sqrt{5} 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

2 5 2\sqrt{5} 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 \sqrt{5} 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Koordinat titik balik dari grafik fungsi kuadrat 𝑦 = −𝑥 2 − 𝑥 + 6 adalah ….

( − 1 2 , 6 1 4 ) \left(-\frac{1}{2},6\ \frac{1}{4}\right) ( − 2 1 , 6 4 1 )

( − 5 , − 2 ) \left(-5,-2\right)\ ( − 5 , − 2 )

( 2 1 2 , − 5 ) \left(2\ \frac{1}{2},\ -5\right) ( 2 2 1 , − 5 )

( − 5 , 2 5 ) \left(-5,\frac{2}{5}\right) ( − 5 , 5 2 )

( 2 , 25 4 ) \left(2,\frac{25}{4}\right) ( 2 , 4 2 5 )

Bentuk sederhana dari 2 3 2 − 5 \frac{2\sqrt{3}}{\sqrt{2\ -\ \sqrt{5}}} 2 − 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> <path d="M263,681c0.7,0,18,39.7,52,119c34,79.3,68.167, 158.7,102.5,238c34.3,79.3,51.8,119.3,52.5,120c340,-704.7,510.7,-1060.3,512,-1067 c4.7,-7.3,11,-11,19,-11H40000v40H1012.3s-271.3,567,-271.3,567c-38.7,80.7,-84, 175,-136,283c-52,108,-89.167,185.3,-111.5,232c-22.3,46.7,-33.8,70.3,-34.5,71 c-4.7,4.7,-12.3,7,-23,7s-12,-1,-12,-1s-109,-253,-109,-253c-72.7,-168,-109.3, -252,-110,-252c-10.7,8,-22,16.7,-34,26c-22,17.3,-33.3,26,-34,26s-26,-26,-26,-26 s76,-59,76,-59s76,-60,76,-60z M1001 80H40000v40H1012z"> 2 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> adalah

− 2 3 ( 6 + 15 ) -\frac{2}{3}\left(\sqrt{6}+\sqrt{15}\right) − 3 2 ( 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

− 2 3 ( 6 − 15 ) -\frac{2}{3}\left(\sqrt{6}-\sqrt{15}\right) − 3 2 ( 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

3 2 ( 15 + 6 ) \frac{3}{2}\left(\sqrt{15}+\sqrt{6}\right) 2 3 ( 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

2 3 ( 6 + 15 ) \frac{2}{3}\left(\sqrt{6}+\sqrt{15}\right) 3 2 ( 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

3 2 ( 6 − 15 ) \frac{3}{2}\left(\sqrt{6}-\sqrt{15}\right) 2 3 ( 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 1 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

Seorang pelukis memeiliki persediaan 80 set cat minyak dan 60 set cat pluto. Sebuah galeri seni menawarkan untuk membuat lukisan natural dan abstrak. Setelah dihitung ternyata sebuah lukisan natural membutuhkan 2 set cat minyak dan 1 set cat pluto, sedangkan lukisan abstrak memerlukan masing-masing 1 set cat. Jika jumlah lukisan natural dinyatakan dalam 𝑥 dan jumlah lukisan abstrak dinyatakan dalam 𝑦, model matematika dari pernyataan di atas adalah ….

2𝑥 + 𝑦 ≤ 80; 𝑥 + 𝑦 ≤ 60; 𝑥 ≥ 0; 𝑦 ≥ 0

𝑥 + 𝑦 ≤ 80; 𝑥 + 2𝑦 ≤ 60; 𝑥 ≥ 0; 𝑦 ≥ 0

𝑥 + 2𝑦 ≤ 80; 𝑥 + 𝑦 ≤ 60; 𝑥 ≥ 0; 𝑦 ≥ 0

2𝑥 + 𝑦 ≤ 80; 2𝑥 + 𝑦 ≤ 60; 𝑥 ≥ 0; 𝑦 ≥ 0

𝑥 + 2𝑦 ≤ 80; 𝑥 + 2𝑦 ≤ 60; 𝑥 ≥ 0; 𝑦 ≥ 0

Jumlah tak hingga dari deret 81 + 27 + 9 + 3 + ⋯ adalah ….

121 1 2 121\ \frac{1}{2} 1 2 1 2 1

121 1 3 121\ \frac{1}{3} 1 2 1 3 1

122 1 2 122\ \frac{1}{2} 1 2 2 2 1

122 1 3 122\ \frac{1}{3} 1 2 2 3 1

Matematika

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Mathematics

12th Grade

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MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Bentuk sederhana dari $\frac{\left(x^2y^3z^{-6}\right)^2}{\left(x^{-2}y^6z^3\right)^3}$ adalah...

$\frac{x^6}{y^{11}z^2}$

$\frac{x^{10}}{y^{12}z^{21}}$

$\frac{x^{12}}{y^{10}z^{21}}$

$\frac{x^{10}y^{12}}{z^{20}}$

$\frac{x^{12}z^{21}}{y^{10}}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Hasil dari $\sqrt{125}-\frac{1}{3}\sqrt{180}+\sqrt{45}-\sqrt{20}$ adalah...

$5\sqrt{5}$

$4\sqrt{5}$

$3\sqrt{5}$

$2\sqrt{5}$

$\sqrt{5}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Persamaan fungsi kuadrat dari grafik diatas adalah ….

$y=-x^2-6x+5$

$y=-x^2+6x-5$

$y=-x^2+6x+5$

$y=x^2-6x+5$

$y=x^2+6x+5$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Suatu fungsi kuadrat memotong sumbu X di titik (−1, 0) dan (4, 0) serta memotong sumbu Y di titik (0, 8). Fungsi kuadrat tersebut adalah …..

𝑓(𝑥) = −2𝑥² − 6𝑥 − 8

𝑓(𝑥) = −2𝑥² − 6𝑥 + 8

𝑓(𝑥) = −2𝑥² + 6𝑥 +8

𝑓(𝑥) = 2𝑥² + 6𝑥 +8

𝑓(𝑥) = 2𝑥² + 6𝑥 - 8

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Koordinat titik balik dari grafik fungsi kuadrat
𝑦 = −𝑥² − 𝑥 + 6 adalah ….

$\left(-5,-2\right)\$

$\left(2\ \frac{1}{2},\ -5\right)$

$\left(-5,\frac{2}{5}\right)$

$\left(2,\frac{25}{4}\right)$

$\left(-\frac{1}{2},6\ \frac{1}{4}\right)$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Bentuk sederhana dari $\frac{2\sqrt{3}}{\sqrt{2\ -\ \sqrt{5}}}$ adalah

$-\frac{2}{3}\left(\sqrt{6}+\sqrt{15}\right)$

$-\frac{2}{3}\left(\sqrt{6}-\sqrt{15}\right)$

$\frac{3}{2}\left(\sqrt{15}+\sqrt{6}\right)$

$\frac{2}{3}\left(\sqrt{6}+\sqrt{15}\right)$

$\frac{3}{2}\left(\sqrt{6}-\sqrt{15}\right)$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika 𝛼 dan 𝛽 merupakan akar-akar dari persamaan kuadrat 2𝑥² − 3𝑥 − 4 = 0, persamaan kuadrat baru yang akar-akarnya (𝛼 − 3) dan (𝛽 − 3) adalah ….

2𝑥² + 5𝑥 + 5 = 0

2𝑥² + 6𝑥 − 5 = 0

2𝑥² − 7𝑥 + 5 = 0

2𝑥² − 8𝑥 − 5 = 0

2𝑥² + 9𝑥 + 5 = 0

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Jika 𝛼 dan 𝛽 merupakan akar persamaan kuadrat $x^2-3x-4=0$ , nilai $\frac{2}{\alpha^2}+\frac{2}{\beta^2}$ adalah ….

$\frac{1}{8}$

$\frac{1}{4}$

$\frac{3}{8}$

$\frac{5}{8}$

$\frac{3}{4}$

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Matematika

Bentuk sederhana dari $\frac{\left(x^2y^3z^{-6}\right)^2}{\left(x^{-2}y^6z^3\right)^3}$ adalah...

Hasil dari $\sqrt{125}-\frac{1}{3}\sqrt{180}+\sqrt{45}-\sqrt{20}$ adalah...

Persamaan fungsi kuadrat dari grafik diatas adalah ….

Suatu fungsi kuadrat memotong sumbu X di titik (−1, 0) dan (4, 0) serta memotong sumbu Y di titik (0, 8). Fungsi kuadrat tersebut adalah …..

Koordinat titik balik dari grafik fungsi kuadrat
𝑦 = −𝑥² − 𝑥 + 6 adalah ….

Bentuk sederhana dari $\frac{2\sqrt{3}}{\sqrt{2\ -\ \sqrt{5}}}$ adalah

Jika 𝛼 dan 𝛽 merupakan akar-akar dari persamaan kuadrat 2𝑥² − 3𝑥 − 4 = 0, persamaan kuadrat baru yang akar-akarnya (𝛼 − 3) dan (𝛽 − 3) adalah ….

Jika 𝛼 dan 𝛽 merupakan akar persamaan kuadrat $x^2-3x-4=0$ , nilai $\frac{2}{\alpha^2}+\frac{2}{\beta^2}$ adalah ….

Harga dua buah buku dan tiga buah pensil adalah Rp14.500,00 sedangkan harga tiga buah buku dan sebuah pensil adalah Rp13.000,00. Jika Fitri membeli masing-masing sebuah buku dan pensil yang sama, ia harus membayar ….

Koordinat bayangan titik 𝐴(4, −1) oleh dilatasi [𝑂, 2] dilanjutkan dengan rotasi 90° searah jarum jam dengan pusat 𝑂(0,0) adalah ….

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Popular Resources on Wayground

Discover more resources for Mathematics

Matematika

Bentuk sederhana dari (x2y3z−6)2(x−2y6z3)3\frac{\left(x^2y^3z^{-6}\right)^2}{\left(x^{-2}y^6z^3\right)^3}(x−2y6z3)3(x2y3z−6)2​ adalah...

Hasil dari 125−13180+45−20\sqrt{125}-\frac{1}{3}\sqrt{180}+\sqrt{45}-\sqrt{20}125​−31​180​+45​−20​ adalah...

Persamaan fungsi kuadrat dari grafik diatas adalah ….

Suatu fungsi kuadrat memotong sumbu X di titik (−1, 0) dan (4, 0) serta memotong sumbu Y di titik (0, 8). Fungsi kuadrat tersebut adalah …..

Koordinat titik balik dari grafik fungsi kuadrat 𝑦 = −𝑥2 − 𝑥 + 6 adalah ….

Bentuk sederhana dari 232 − 5\frac{2\sqrt{3}}{\sqrt{2\ -\ \sqrt{5}}}2 − 5​​23​​ adalah

Jika 𝛼 dan 𝛽 merupakan akar-akar dari persamaan kuadrat 2𝑥2 − 3𝑥 − 4 = 0, persamaan kuadrat baru yang akar-akarnya (𝛼 − 3) dan (𝛽 − 3) adalah ….

Jika 𝛼 dan 𝛽 merupakan akar persamaan kuadrat x2−3x−4=0x^2-3x-4=0x2−3x−4=0 , nilai 2α2+2β2\frac{2}{\alpha^2}+\frac{2}{\beta^2}α22​+β22​ adalah ….

Harga dua buah buku dan tiga buah pensil adalah Rp14.500,00 sedangkan harga tiga buah buku dan sebuah pensil adalah Rp13.000,00. Jika Fitri membeli masing-masing sebuah buku dan pensil yang sama, ia harus membayar ….

Koordinat bayangan titik 𝐴(4, −1) oleh dilatasi [𝑂, 2] dilanjutkan dengan rotasi 90° searah jarum jam dengan pusat 𝑂(0,0) adalah ….

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Bentuk sederhana dari $\frac{\left(x^2y^3z^{-6}\right)^2}{\left(x^{-2}y^6z^3\right)^3}$ adalah...

Hasil dari $\sqrt{125}-\frac{1}{3}\sqrt{180}+\sqrt{45}-\sqrt{20}$ adalah...

Koordinat titik balik dari grafik fungsi kuadrat
𝑦 = −𝑥² − 𝑥 + 6 adalah ….

Bentuk sederhana dari $\frac{2\sqrt{3}}{\sqrt{2\ -\ \sqrt{5}}}$ adalah

Jika 𝛼 dan 𝛽 merupakan akar-akar dari persamaan kuadrat 2𝑥² − 3𝑥 − 4 = 0, persamaan kuadrat baru yang akar-akarnya (𝛼 − 3) dan (𝛽 − 3) adalah ….

Jika 𝛼 dan 𝛽 merupakan akar persamaan kuadrat $x^2-3x-4=0$ , nilai $\frac{2}{\alpha^2}+\frac{2}{\beta^2}$ adalah ….