Solve for h, S = 2 π r h 2\pi rh 2 π r h

h= S 2 π r \frac{S}{2\pi r} 2 π r S

h = S − 2 π r S-2\pi r S − 2 π r

h = 2 π r S \frac{2\pi r}{S} S 2 π r

A = b h 2 A=\frac{bh}{2} A = 2 b h Solve for b

b = 2 A h b=\frac{2A}{h} b = h 2 A

b = 2 A − h b=2A-h b = 2 A − h

b = A h 2 b=\frac{Ah}{2} b = 2 A h

b = A − 2 h b=\frac{A-2}{h} b = h A − 2

Solve for x y = mx + b

x = y − b m x=\frac{y-b}{m} x = m y − b

x = y b m x=\frac{yb}{m} x = m y b

x = y + b m x=\frac{y+b}{m} x = m y + b

T = p + prt Solve for r

r = T − p p t r=\frac{T-p}{pt} r = p t T − p

r = T p − p t r=Tp-pt r = T p − p t

r = T p p t r=\frac{Tp}{pt} r = p t T p

r = T − p − p t r=T-p-pt r = T − p − p t

p = 2 l + 2 w p\ =\ 2l\ +\ 2w p = 2 l + 2 w solve for w

w = p − 2 l 2 w=\frac{p-2l}{2} w = 2 p − 2 l

w = p 2 l − 2 w=\frac{p}{2l}-2 w = 2 l p − 2

w = p + 2 l 2 w=\frac{p+2l}{2} w = 2 p + 2 l

w = 2 p − l w=2p-l w = 2 p − l

V = 1 3 B h V=\frac{1}{3}Bh V = 3 1 B h Solve for h

h = 3 V B h=\frac{3V}{B} h = B 3 V

h = 1 3 V − B h=\frac{1}{3}V-B h = 3 1 V − B

h = 1 3 V B h=\frac{\frac{1}{3}V}{B} h = B 3 1 V

h = 3 V − B h=3V-B h = 3 V − B

P = a + (n - 1)b Solve for b

b = P − a n − 1 b=\frac{P-a}{n-1} b = n − 1 P − a

b = P a + ( n − 1 ) b=\frac{P}{a+\left(n-1\right)} b = a + ( n − 1 ) P

b = P a − ( n − 1 ) b=\frac{P}{a}-\left(n-1\right) b = a P − ( n − 1 )

b = P n − 1 − a b=\frac{P}{n-1}-a b = n − 1 P − a

F = 9 5 C + 32 F=\frac{9}{5}C+32 F = 5 9 C + 3 2 Solve for C

C = 5 9 ( F − 32 ) C=\frac{5}{9}\left(F-32\right) C = 9 5 ( F − 3 2 )

C = 9 5 ( F − 32 ) C=\frac{9}{5}\left(F-32\right) C = 5 9 ( F − 3 2 )

C = 9 5 F − 32 C=\frac{9}{5}F-32 C = 5 9 F − 3 2

C = 5 9 F − 32 C=\frac{5}{9}F\ -32 C = 9 5 F − 3 2

Solving literal Equations

Authored by Andrew Berge

Mathematics

7th Grade

CCSS covered

Used 5+ times

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25 questions

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MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for x:

x = yb - v

x = by - v

x = by + v

Tags

CCSS.HSA.REI.B.3

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

8x + 4y= 16 for y

y = -8x + 16

y = 2x -4

y = -2x + 4

y = -8x + 12

Tags

CCSS.6.EE.C.9

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve the formula for b. What is the 1st step?

Subtract h from each side.

Add h to each side.

Divide each side by h.

Multiply each side by 2.

Tags

CCSS.HSA.REI.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve the literal equation for the given variable.

2A/h

2/(h)

2Ah

Ah/2

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for w:
A = LW

A =^L/_W

w = ^L/_A

w = A

w = ^A/_L

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

h=V/(3πr²)

h=(3V)/(πr²)

h=V/(3πr²)

h=(3π)/(Vr²)

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve the equation for w. ^{x = w / a}

w = a / x

w = x / a

w = ax

x = wa

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for T, B = T - Lc

T = BLc

T = B - Lc

T = $\frac{B}{Lc}$

T = B + Lc

Tags

CCSS.HSA.CED.A.4

10.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Solve for h, S = $2\pi rh$

h= $\frac{S}{2\pi r}$

h = $S2\pi r$

h = $S-2\pi r$

h = $\frac{2\pi r}{S}$

Tags

CCSS.HSA.CED.A.4

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Solving literal Equations

Solve for x:

8x + 4y= 16 for y

Solve the formula for b. What is the 1st step?

Solve the literal equation for the given variable.

Solve for w:A = LW

Solve the equation for w. x = w / a

Solve the equation for x. y = x / w

Solve for T, B = T - Lc

Solve for h, S = 2πrh2\pi rh2πrh

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Solve for w:
A = LW

Solve the equation for w. ^{x = w / a}

Solve the equation for x.
y = x / w

Solve for h, S = $2\pi rh$