2 4 \frac{2}{4} 4 2 + 1 2 \frac{1}{2} 2 1 x 3 5 \frac{3}{5} 5 3 = . . . .

B. 16 20 \frac{16}{20} 2 0 1 6 = 4 5 \frac{4}{5} 5 4

A. 12 20 \frac{12}{20} 2 0 1 2 = 3 5 \frac{3}{5} 5 3

C. 14 20 \frac{14}{20} 2 0 1 4 = 7 10 \frac{7}{10} 1 0 7

D. 18 20 \frac{18}{20} 2 0 1 8 = 9 10 \frac{9}{10} 1 0 9

3 5 \frac{3}{5} 5 3 : 2 4 \frac{2}{4} 4 2 - 2 6 \frac{2}{6} 6 2 = . . . .

A. 26 30 \frac{26}{30} 3 0 2 6 = 13 15 \frac{13}{15} 1 5 1 3

C. 24 30 \frac{24}{30} 3 0 2 4 = 12 15 \frac{12}{15} 1 5 1 2 = 4 5 \frac{4}{5} 5 4

B. 22 30 \frac{22}{30} 3 0 2 2 = 11 15 \frac{11}{15} 1 5 1 1

D. 20 30 \frac{20}{30} 3 0 2 0 = 2 3 \frac{2}{3} 3 2

5 7 ÷ 2 4 − 1 6 = . . . . \frac{5}{7}\div\frac{2}{4}-\frac{1}{6}=\ .\ .\ .\ .\ \ \ 7 5 ÷ 4 2 − 6 1 = . . . .

B. 1 11 42 1\ \frac{11}{42} 1 4 2 1 1

A. 2 11 22 2\ \frac{11}{22} 2 2 2 1 1

OPERASI HITUNG CAMPURAN BILANGAN CACAH, PECAHAN, DAN DESIMAL

6th Grade

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OPERASI HITUNG CAMPURAN BILANGAN CACAH, PECAHAN, DAN DESIMAL

Quiz

•

Mathematics

•

6th Grade

•

Practice Problem

•

Medium

•

CCSS

5.NF.B.4, 5.NF.A.1, 5.NF.B.6

Standards-aligned

Arum Febriyani

Used 38+ times

FREE Resource

10 questions

Show all answers

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$2\frac{1}{3}\times5\%+0,45=\ .\ .\ .\ .\ \ \$

A. $\frac{16}{30}$

C. $\frac{17}{30}$

B. $\frac{18}{30}$

D. $\frac{19}{30}$

Tags

CCSS.5.NBT.B.7

CCSS.5.NF.B.4

CCSS.5.NF.B.5

CCSS.5.NF.B.6

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$2\frac{4}{5}\times\frac{1}{8}-0,25=\ .\ .\ .\ .\ \ \$

A. $\frac{1}{100}$

C. $\frac{1}{10}$

B. $\frac{3}{20}$

D. $\frac{7}{20}$

Tags

CCSS.5.NBT.B.7

CCSS.5.NF.B.4

CCSS.5.NF.B.6

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$Hasil\ dari\ \frac{7}{9}+\ \frac{2}{3}\ -\ \frac{2}{5}\ adalah\ \ .\ .\ .\ .\ \ \ \$

A. $\frac{65}{45}$

C. $\frac{13}{9}$

B. $\frac{45}{47}$

D. $\frac{47}{45}$

Tags

CCSS.5.NF.A.1

CCSS.5.NF.A.2

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\frac{2}{4}$ + $\frac{1}{2}$ x $\frac{3}{5}$ = . . . .

A. $\frac{12}{20}$ = $\frac{3}{5}$

C. $\frac{14}{20}$ = $\frac{7}{10}$

B. $\frac{16}{20}$ = $\frac{4}{5}$

D. $\frac{18}{20}$ = $\frac{9}{10}$

Tags

CCSS.5.NF.A.1

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\frac{3}{5}$ : $\frac{2}{4}$ - $\frac{2}{6}$ = . . . .

A. $\frac{26}{30}$ = $\frac{13}{15}$

C. $\frac{24}{30}$ = $\frac{12}{15}$ = $\frac{4}{5}$

B. $\frac{22}{30}$ = $\frac{11}{15}$

D. $\frac{20}{30}$ = $\frac{2}{3}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\frac{4}{9\ }\ X\ \left(\ \frac{8}{9}\ -\ \frac{6}{9}\right)\ =\ \ .\ .\ .\ .\ \ \ \$

A. $\frac{4}{81}$

C. $\frac{6}{81}$

B. $\frac{8}{81}$

D. $\frac{10}{81}$

Tags

CCSS.5.NF.B.4

CCSS.5.NF.B.5

CCSS.5.NF.B.6

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

$\frac{5}{7}\div\frac{2}{4}-\frac{1}{6}=\ .\ .\ .\ .\ \ \$

A. $2\ \frac{11}{22}$

C. $\frac{11}{42}$

B. $1\ \frac{11}{42}$

D. $\frac{12}{42}$

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OPERASI HITUNG CAMPURAN BILANGAN CACAH, PECAHAN, DAN DESIMAL

10 questions

$2\frac{1}{3}\times5\%+0,45=\ .\ .\ .\ .\ \ \$

$2\frac{4}{5}\times\frac{1}{8}-0,25=\ .\ .\ .\ .\ \ \$

$Hasil\ dari\ \frac{7}{9}+\ \frac{2}{3}\ -\ \frac{2}{5}\ adalah\ \ .\ .\ .\ .\ \ \ \$

$\frac{2}{4}$ + $\frac{1}{2}$ x $\frac{3}{5}$ = . . . .

$\frac{3}{5}$ : $\frac{2}{4}$ - $\frac{2}{6}$ = . . . .

$\frac{4}{9\ }\ X\ \left(\ \frac{8}{9}\ -\ \frac{6}{9}\right)\ =\ \ .\ .\ .\ .\ \ \ \$

$\frac{5}{7}\div\frac{2}{4}-\frac{1}{6}=\ .\ .\ .\ .\ \ \$

$\frac{6}{7}-\frac{1}{9}\div\frac{2}{9}\ =\ .\ .\ .\ .\$

Ani membuat tongkat sepanjang $1\ \frac{1}{2}$ meter dan Santi membuat tongkat sepanjang $2\ \frac{1}{4}$ meter. Total panjang tongkat mereka berdua adalah .... meter

Hasil dari
$\frac{3}{8}$ x $1\frac{3}{5}$ : $\frac{1}{4}$ adalah ... .

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Popular Resources on Wayground

Discover more resources for Mathematics

OPERASI HITUNG CAMPURAN BILANGAN CACAH, PECAHAN, DAN DESIMAL

10 questions

213×5%+0,45= . . . . 2\frac{1}{3}\times5\%+0,45=\ .\ .\ .\ .\ \ \ 231​×5%+0,45= . . . .

245×18−0,25= . . . . 2\frac{4}{5}\times\frac{1}{8}-0,25=\ .\ .\ .\ .\ \ \ 254​×81​−0,25= . . . .

Hasil dari 79+ 23 − 25 adalah . . . . Hasil\ dari\ \frac{7}{9}+\ \frac{2}{3}\ -\ \frac{2}{5}\ adalah\ \ .\ .\ .\ .\ \ \ \ Hasil dari 97​+ 32​ − 52​ adalah . . . .

24\frac{2}{4}42​ + 12\frac{1}{2}21​ x 35\frac{3}{5}53​ = . . . .

35\frac{3}{5}53​ : 24\frac{2}{4}42​ - 26\frac{2}{6}62​ = . . . .

49 X ( 89 − 69) = . . . . \frac{4}{9\ }\ X\ \left(\ \frac{8}{9}\ -\ \frac{6}{9}\right)\ =\ \ .\ .\ .\ .\ \ \ \ 9 4​ X ( 98​ − 96​) = . . . .

57÷24−16= . . . . \frac{5}{7}\div\frac{2}{4}-\frac{1}{6}=\ .\ .\ .\ .\ \ \ 75​÷42​−61​= . . . .

67−19÷29 = . . . . \frac{6}{7}-\frac{1}{9}\div\frac{2}{9}\ =\ .\ .\ .\ .\ 76​−91​÷92​ = . . . .

Ani membuat tongkat sepanjang 1 121\ \frac{1}{2}1 21​ meter dan Santi membuat tongkat sepanjang 2 142\ \frac{1}{4}2 41​ meter. Total panjang tongkat mereka berdua adalah .... meter

Hasil dari 38\frac{3}{8}83​ x 1351\frac{3}{5}153​ : 14\frac{1}{4}41​ adalah ... .

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$2\frac{1}{3}\times5\%+0,45=\ .\ .\ .\ .\ \ \$

$2\frac{4}{5}\times\frac{1}{8}-0,25=\ .\ .\ .\ .\ \ \$

$Hasil\ dari\ \frac{7}{9}+\ \frac{2}{3}\ -\ \frac{2}{5}\ adalah\ \ .\ .\ .\ .\ \ \ \$

$\frac{2}{4}$ + $\frac{1}{2}$ x $\frac{3}{5}$ = . . . .

$\frac{3}{5}$ : $\frac{2}{4}$ - $\frac{2}{6}$ = . . . .

$\frac{4}{9\ }\ X\ \left(\ \frac{8}{9}\ -\ \frac{6}{9}\right)\ =\ \ .\ .\ .\ .\ \ \ \$

$\frac{5}{7}\div\frac{2}{4}-\frac{1}{6}=\ .\ .\ .\ .\ \ \$

$\frac{6}{7}-\frac{1}{9}\div\frac{2}{9}\ =\ .\ .\ .\ .\$

Ani membuat tongkat sepanjang $1\ \frac{1}{2}$ meter dan Santi membuat tongkat sepanjang $2\ \frac{1}{4}$ meter. Total panjang tongkat mereka berdua adalah .... meter

Hasil dari
$\frac{3}{8}$ x $1\frac{3}{5}$ : $\frac{1}{4}$ adalah ... .