Multiply/Divide One Step Equations

In order to solve equations, we use _______ __________ to undo the operations on the variable.

Tags

CCSS.6.EE.B.7

The inverse of multiplication is ________.

Tags

CCSS.6.EE.B.7

Solve the equation. 

 $\frac{k}{4}=8$  

Tags

CCSS.6.EE.B.7

Solve the equation.

 $4x=28$  

Tags

CCSS.6.EE.B.7

What is the first step to solving this equation?

 $-64=8c$  

• Divide both sides by 8

• Multiply both sides by 8

• Divide both sides by 8c

• Subtract 8 from both sides.

• Multiply both sides by 64

Tags

CCSS.HSA.REI.A.1

What is the first step to solving this equation?

 $\frac{z}{3}=-9$  

• Multiply both sides by 3

• Divide both sides by 3

• Multiply both sides by -9

• Add nine to both sides. 

• Subtract 3 from both sides. 

Tags

CCSS.6.EE.B.7

An orange contains about 80 milligrams of vitamin C, which is 10 times as much as an apple contains. Which equation could help us find the amount of vitamin C in an apple?

• $10a=80$

• $\frac{a}{10}=80$

• $80a=10$

• $\frac{a}{80}=10$

• $a+10=80$

Tags

CCSS.HSA.CED.A.3

For the equation $\frac{x}{3}=15$ , a student found the value of  $x$ to be 5. Is the student correct? Why or why not?

• The student is correct because they divided both sides correctly by 3 and 15 divided by 3 is 5. 

• The student is not correct because while they divided both sides by 3 correctly, 15 divided by 3 is not 5. 

• The student is not correct because they should have multiplied both sides by 3 instead of dividing both sides by 3. 

• The student is not correct because instead of dividing both sides by 3 they should have added 3 to both sides. 

Tags

CCSS.HSA.REI.A.1

Solve the equation.  $-9=p-2$  

Tags

CCSS.6.EE.B.7

 $19+a=19$  

Tags

CCSS.6.EE.B.7