Solving Polynomials with Grouping

Factor by grouping
x³ - 4x² -4x + 16

• (x+4)(x+2)
• (x-4)(x² -4) 
• (x+4)(x² -4)
• (x-4)(x-2)

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Now that you have factored the following. Solve for x. (Hint: You will have to use the Difference of Squares Method)
 $x^3-4x^2-4x+16$  

For example you might write: x = -10, 10, and 12.
Use this format with the correct numbers

Factor by grouping:
4p³+8p²+3p+6

• (2p²+3)(p+2)
• (2p²+6)(p+4)
• (4p²+3)(p+2)
• (4p²+8p)(3p+6)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor by grouping:
x³+7x²-2x-14

• (x²-2)(x-7)
• (x²+2)(x-7)
• (x²+2)(x+7)
• (x²-2)(x+7)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor by grouping:
x³+7x²-2x-14

• (x²-2)(x-7)
• (x²+2)(x-7)
• (x²+2)(x+7)
• (x²-2)(x+7)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor by grouping:
5n³-10n²+3n-6

• (5n²+3)(n-2)
• (5n²-3)(n-2)
• (5n³+3)(n-2)
• 10n(n²-6)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Factor by grouping:
5n³-10n²+3n-6

• (5n²+3)(n-2)
• (5n²-3)(n-2)
• (5n³+3)(n-2)
• 10n(n²-6)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

30x³+15x²-18x-9

• (5x²-3)(6x+1)
• (5x²-3)(6x+3)
• 3(5x²+3)(2x-1)
• 3(5x²-3)(2x+1)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

x³-5x²+5x-25

• (x²-5)(x-5)
• (x²+5)(x-5)
• (x²+5)(x+5)
• (x²-1)(x-25)

Tags

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

2x³-8x²-x+4

• (2x²-1)(x-4)
• 2(x²-1)(x+4)
• (x²-1)(2x-4)
• (2x²+1)(x-4)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3