I = p r t ; f o r r I=prt;\ for\ r I = p r t ; f o r r

r = I p t r=\frac{I}{pt} r = p t I

r = t p I r=\frac{t}{pI} r = p I t

r = p I t r=\frac{p}{It} r = I t p

a x − 5 = b ; f o r a ax-5\ =\ b;\ for\ a a x − 5 = b ; f o r a

( b + 5 ) x \frac{\left(b+5\right)}{x} x ( b + 5 )

x ( b + 5 ) x\left(b+5\right) x ( b + 5 )

( b − 5 ) x \frac{\left(b-5\right)}{x} x ( b − 5 )

x ( b − 5 ) x\left(b-5\right) x ( b − 5 )

C = 2 π r ; f o r π C=2\pi r;\ for\ \pi C = 2 π r ; f o r π

π = C 2 r \pi=\frac{C}{2r} π = 2 r C

π = 2 r C \pi=\frac{2r}{C} π = C 2 r

π = r 2 C \pi=\frac{r}{2C} π = 2 C r

Rearranging formula starter

Authored by Gerhard Van Der Wal

Mathematics

9th - 10th Grade

CCSS covered

Used 108+ times

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8 questions

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

d = rt, for r

r=t/d

r=dt

r = 𝒅/t

r=td

Tags

CCSS.7.NS.A.2C

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$I=prt;\ for\ r$

$r=pIt$

$r=\frac{I}{pt}$

$r=\frac{t}{pI}$

$r=\frac{p}{It}$

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$ax-5\ =\ b;\ for\ a$

$x\left(b+5\right)$

$\frac{\left(b-5\right)}{x}$

$\frac{\left(b+5\right)}{x}$

$x\left(b-5\right)$

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Make a the subject of
a + b = c

a = c - b

a = b - c

a = b + c

a = bc

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Make w the subject of
A = lw

w = A/l

w = l/A

w = A - l

w = Al

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Solve for y:
3x + y = 12

y = -3x +12

x = y + 4

x = y + 12

y = 3x -12

Tags

CCSS.6.EE.C.9

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$C=2\pi r;\ for\ \pi$

$\pi=\frac{C}{2r}$

$\pi=\frac{2r}{C}$

$\pi=C2r$

$\pi=\frac{r}{2C}$

Tags

CCSS.HSA.CED.A.4

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$3b=6v-3b;\ for\ v$

$6b-6$

$b$

$b-6$

$0$

Tags

CCSS.HSA.CED.A.4

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.3

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Rearranging formula starter

d = rt, for r

I=prt; for rI=prt;\ for\ rI=prt; for r

ax−5 = b; for aax-5\ =\ b;\ for\ aax−5 = b; for a

Make a the subject ofa + b = c

Make w the subject of A = lw

Solve for y:3x + y = 12

C=2πr; for πC=2\pi r;\ for\ \piC=2πr; for π

3b=6v−3b; for v3b=6v-3b;\ for\ v3b=6v−3b; for v

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Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

$I=prt;\ for\ r$

$ax-5\ =\ b;\ for\ a$

Make a the subject of
a + b = c

Make w the subject of
A = lw

Solve for y:
3x + y = 12

$C=2\pi r;\ for\ \pi$

$3b=6v-3b;\ for\ v$