1 81 = 3 − 4 \frac{1}{81}=3^{-4} 8 1 1 = 3 − 4 , significa que:

log ⁡ 3 ( 1 81 ) = − 4 \log_3\left(\frac{1}{81}\right)=-4 lo g 3 ( 8 1 1 ) = − 4

log ⁡ 4 ( 1 81 ) = − 3 \log_4\left(\frac{1}{81}\right)=-3 lo g 4 ( 8 1 1 ) = − 3

log ⁡ 3 ( 1 81 ) = 4 \log_3\left(\frac{1}{81}\right)=4 lo g 3 ( 8 1 1 ) = 4

log ⁡ − 3 ( 81 ) = 4 \log_{-3}\left(81\right)=4 lo g − 3 ( 8 1 ) = 4

log ⁡ x ( 4 m a p ) \log_x\left(4map\right) lo g x ( 4 m a p )

log ⁡ x 4 + log ⁡ x m + log ⁡ x a + log ⁡ x p \log_x4\ +\log_xm+\log_xa+\log_xp lo g x 4 + lo g x m + lo g x a + lo g x p

log ⁡ x y + log ⁡ x 5 \log_xy\ +\log_x5 lo g x y + lo g x 5

log ⁡ x 4 + log ⁡ x 10 + log ⁡ x 8 \log_x4+\ \log_x10+\log_x8 lo g x 4 + lo g x 1 0 + lo g x 8

log ⁡ x ( 9 b ) \log_x\left(\frac{9}{b}\right) lo g x ( b 9 )

log ⁡ x 9 − log ⁡ x b \log_x9\ -\log_xb lo g x 9 − lo g x b

log ⁡ x b − log ⁡ x 9 \log_xb\ -\log_x9 lo g x b − lo g x 9

log ⁡ x 5 − log ⁡ x 9 \log_x5\ -\log_x9 lo g x 5 − lo g x 9

log ⁡ b ( 2 h 6 p ) \log_b\left(\frac{2h}{6p}\right) lo g b ( 6 p 2 h )

log ⁡ b 2 + log ⁡ b h − log ⁡ b 6 − log ⁡ b p \log_b2\ +\log_bh\ -\log_b6\ -\log_bp lo g b 2 + lo g b h − lo g b 6 − lo g b p

log ⁡ b 2 + log ⁡ b h + log ⁡ b 6 + log ⁡ b p \log_b2\ +\log_bh\ +\log_b6\ +\log_bp lo g b 2 + lo g b h + lo g b 6 + lo g b p

log ⁡ b 2 + log ⁡ b h + log ⁡ b 2 + log ⁡ b h \log_b2\ +\log_bh\ +\log_b2\ +\log_bh lo g b 2 + lo g b h + lo g b 2 + lo g b h

log ⁡ z 4 − log ⁡ z p + log ⁡ z e \log_z4\ -\log_z\ p+\log_z\ e lo g z 4 − lo g z p + lo g z e

log ⁡ x ( 4 e p ) \log_x\left(\frac{4e}{p}\right) lo g x ( p 4 e )

log ⁡ x ( 4 r 2 p ) \log_x\left(\frac{4r}{2p}\right) lo g x ( 2 p 4 r )

log ⁡ x ( 4 e o ) \log_x\left(\frac{4e}{o}\right) lo g x ( o 4 e )

Logaritmos Propiedades

Authored by Javier Matemáticas

Mathematics

11th - 12th Grade

CCSS covered

Used 27+ times

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\log_327=$

Tags

CCSS.HSF.BF.B.5

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\log_{30}1=$

-1

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

El valor de x en la siguiente igualdad Log_x9 = 2 es.....

Tags

CCSS.HSF.BF.B.5

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Log 10000

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

El valor de y en la siguiente igualdad Log₁₀y=3 es....

100

1000

10000

Tags

CCSS.HSF.BF.B.5

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

¿Cuál es el valor de Log₀1 ?

obvio que 1

obvio que 0

obvio que -1

obvio que no se puede

Tags

CCSS.HSF.BF.B.5

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\log_5125=3$ , significa que:

$5^3=125$

$3^5=125$

$\frac{125}{5}=25$

Tags

CCSS.HSF.BF.B.5

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\frac{1}{81}=3^{-4}$ , significa que:

$\log_3\left(\frac{1}{81}\right)=-4$

$\log_4\left(\frac{1}{81}\right)=-3$

$\log_3\left(\frac{1}{81}\right)=4$

$\log_{-3}\left(81\right)=4$

Tags

CCSS.HSF.BF.B.5

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\log_{16}2\$
Calcule

1/4

1/2

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$\log_{\sqrt{2}}2=$
Calcule

1/2

-2

Ninguna

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Logaritmos Propiedades

log⁡327=\log_327=log3​27=

log⁡301=\log_{30}1=log30​1=

El valor de x en la siguiente igualdad Logx 9 = 2 es.....

Log 10000

El valor de y en la siguiente igualdad Log10 y=3 es....

¿Cuál es el valor de Log01 ?

log⁡5125=3\log_5125=3log5​125=3 , significa que:

181=3−4\frac{1}{81}=3^{-4}811​=3−4 , significa que:

log⁡162 \log_{16}2\ log16​2 Calcule

log⁡22=\log_{\sqrt{2}}2=log2​​2= Calcule

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$\log_327=$

$\log_{30}1=$

El valor de x en la siguiente igualdad Log_x9 = 2 es.....

El valor de y en la siguiente igualdad Log₁₀y=3 es....

¿Cuál es el valor de Log₀1 ?

$\log_5125=3$ , significa que:

$\frac{1}{81}=3^{-4}$ , significa que:

$\log_{16}2\$
Calcule

$\log_{\sqrt{2}}2=$
Calcule