Grade 11, Maths/ Chapter (5) - Sequences and Series

The (n – 2)^th term of an A.P. is n + 2. Then the (n + 2)^th term is

• n + 6

• n + 5

• n + 4

• n – 2

If the first term of an A.P. is 10 and 25^th term is 82, then the common difference is

• 1

• 3

• 4

• -2

If 2, x, y, 11, z an A.P., then z – y =

• 1

• 3

• 6

• -2

The value of a for which 6a – 2, 3a, a + 2 is an A.P. is

• 2

• 1

• 6

• 0

In an A.P., the fourth term is 6. Then S₇ =

• 42

• 15

• 46

• 50

If the 6^th term of an A.P. is 20, then the sum of first 11 terms is

• 420

• 220

• 246

• 150

The first term and n^th term of an A.P. are 5 and 25 respectively, the sum of first n^th term is 135, then n =

• 2

• 7

• 9

• 10

The sum of three A.M. between 7 and – 5 is

• 1

• 0

• 6

• 3

 $The\ common\ ratio\ of\ \frac{1}{10^5},\ \frac{1}{10^3},\ \frac{1}{10},\ .\ .\ .$  

•  $100$  

•  $\frac{1}{100}$  

•  $-100$  

•  $10$  

Given that 8, x + 5, 18, 27 are positive consecutive terms of G.P., then x =

• 2

• 7

• 9

• 10