Factoring Polynomials with tables and division

Using the area model, solve  $\frac{x^3+3x^2-6x-8}{x+1}$  

•  $x^2+2x-8$  
  

•  $x^2-x-2$  
  

•  $x^2+4x+4$  
  

•  $x^2+3x+4$  
  

Tags

CCSS.HSA.APR.D.6

Multiply together the factored form to get the polynomial form (Hint, you'll need 2 different boxes to do it)
 $(x-2)(x-2)(x+3)$  

•  $3x^3-4x+3$  
  

•  $x^3-x^2-8x+12$  

•  $x^3+1$  
  

•  $x^3-8x^2+12-8$ 

Tags

CCSS.HSA.APR.A.1

 $x^2-8x+15$  

What are the factors of

• (x-2)(x+4)

• (x-5)(x-3)

• (x+5)(x+3)

• This polynomial cannot be factored with real numbers

Using either the area model or the remainder theorem, is (x+4) a factor of x³+7x²+16x+16?

• A) Yes, because it divides without a remainder

• B) Yes, because if I plug in -4 for x, I get 0 as an answer

• C) No, because 4 is not a factor of 7

• D) No, because polynomials with a degree of 3 don't have factors

• E) A and B

Tags

CCSS.HSA.APR.B.2

Use some combination of Graphs and Polynomial division to factor 2x³-12x²+26x-24

• (2x-3)(x+4)(x-1)

• (x-3)³

• (x-3)(2x²-6x+8)

• (x+3)³

Tags

CCSS.HSA.APR.B.2

 $x^2+3x-8$  

What are the factors of

• (x+3)(x+8)

• (x-2)(x+4)

• (x+1)(x+2)

• It cannot be factored using real numbers

What is an imaginary number? 

• i, which equals  $\sqrt{-1}$  

• A number so big you can't name it

• A number so small you can't name it

• n, which equals  $\sqrt{-5}$  

 $\frac{x^4-3x^3+4x^2-8x+1}{x-4}$  

(Use the area model to solve)

•  $x^3+x^2+8x+24+\frac{97}{x-4}$  

•  $2x^3+3x^2+9x+25+\frac{98}{x-4}$  

•  $\ x^3-7x^2+x-12+\frac{1}{x-4}$  

•  $x^3+2x^2+3x+4$  

Tags

CCSS.HSA.APR.D.6

Use a combination of Graphs and division to factor  $x^4+2x^3+3x^2+4x+2$  as far as possible

•  $(x+1)^2(x^2+2)$  

• Not factorable with real numbers

•  $x^3+x^2+2x+2$  

•  $\left(x+1\right)\left(x+1\right)\left(x+1\right)\left(x+1\right)$  

Tags

CCSS.HSA.APR.B.2

 $x^2+6x-40$  

What are the factors of

• (x-4)(x+10)

• (x+4)(x-10)

• (x+20)(x-2)

• Cannot be factored with real numbers