Equations Recap

In the equation

x + 7 = 12

7 is being added to the variable, x.

How should you show your work to isolate the variable and solve the equation?

• Subtract 7 from both sides. The solution is x = 5.

• Add 7 to both sides.

  The solution is x = 19.

• Multiply both sides by 7 The solution is x = 84.

Tags

CCSS.6.EE.B.7

 $16\ =\frac{k}{11}$  

The variable, k, is being divided by 11. What step needs to be completed to isolate the variable k?

• Divide both sides by 11

• Multiply both sides by 11.

• Add 11 to both sides.

• Subtract 11 to both sides.

Tags

CCSS.6.EE.B.7

Solve for x in the following equation:

20.5 = x + 4

• 16.5

• 16.05

• 24.5

• 24.05

Tags

CCSS.6.EE.B.7

Solve for z in the following equation:

z - 33 = 147

• z= 114

• z = 177

• z = 180

• No Solution

Tags

CCSS.6.EE.B.7

10x + 9 = 4x - 9

• x = 0

• x = 3

• x = -3

• x = -18

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

CCSS.6.EE.A.2

-5k + 10 = -2k - 14

• k = 8

• k = -8

• k = 2

• k = -2

Tags

CCSS.6.EE.B.5

CCSS.6.EE.B.6

What is the first step to solve this equation:

- 3x -11 = 44

• Add 3 to both sides

• Subtract 11 from both sides

• Add 11 to both sides

• Divide 3 on both sides.

Tags

CCSS.7.EE.B.4A

The steps in solving 5b - 6 = 24 are: 

• Add 6 to both sides and divide both sides by 5
• Add 6 to both sides and multiply both sides by 5
• Subtract 6 from both sides then multiply both sides by 5
• Subtract 6 from both sides then divide both sides by 5

Tags

CCSS.7.EE.B.4A

Solve for x:

2x - 3 = 1

• x = 3

• x = 2

• x = 1

• x = -2

Tags

CCSS.7.EE.B.4A

Solve for b:
 3(b - 4) = -3

• b = 3
• b = -3
• b = 5
• b = -5

Tags

CCSS.7.EE.B.4A