Continuously Compound Interest Bellwork

Bruno was given $2000 at birth . His parents invested it at a 2% interest rate compounded annually. No deposits or withdrawls were made. Which expression can be used to determine how much money Bruno had in the account when he turned 13?

• 2000(1+0.02)¹³

• 2000(1-0.02)¹³

• 2000(1+0.02)¹⁶

• 2000(1-0.02)¹⁶

Tags

CCSS.HSF.BF.A.2

Mary-Kayla deposits $88,000 in a bank at an interest rate of 2.8% for t years, compounded quarterly. Pick the correct equation.

• $y=88000\left(1+\frac{0.028}{4}\right)^{4t}$

• $y=88000\left(1.028\right)^t$
  

• $y=88000\left(1.028\right)^{4t}$
  

• $y=88000\left(1+\frac{4}{0.028}\right)^{0.028t}$

Principal: $5000

Interest Rate: 3.75%

Time: 25 years

Compounded Monthly

State the future account balance.

• $y=5000\left(1.0375\right)^x$

• $y=5000\left(1+\frac{0.0375}{12}\right)^{12t}$

• $y=5000\left(1+\frac{12}{0.0375}\right)^{0.0375t}$

• $y=5000\left(1+\frac{0.375}{12}\right)^{12t}$
  

What is the growth rate for the equation?

y = 200(1.8^x)

• 200

• 1.8

• 80%

Tags

CCSS.HSF-IF.C.8B

Sally invests $750 dollars into a bank that pays 7% interest.

What is the growth rate?

• 750

• 1.7

• 1.07

• 7%

Tags

CCSS.HSF-IF.C.8B

A population of 1500 deer decreases by 1.5% per year. At the end of 10 years, there will be approximately 1290 deer in the population. Which function can be used to determine the number of deer, y, in this population at the end of t years?

• y = 1500(1 - 0.015)^t
• y = 1500(0.015)^t
• y = 1500(1 + 0.015)^t
• y = 1500(1.5)^t

Tags

CCSS.HSF.LE.A.2