El conjugado de la expresión x − 4 − 3 \sqrt{x-4}-3 x − 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 3 es:

x − 4 + 3 \sqrt{x-4}+3 x − 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 3

x + 4 − 3 \sqrt{x+4}-3 x + 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 3

x + 4 + 3 \sqrt{x+4}+3 x + 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 3

− x − 4 + 3 -\sqrt{x-4}+3 − x − 4 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 3

Límites indeterminados 0/0

Authored by ROMÁN CLEMENTE

Mathematics

12th Grade

Used 49+ times

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12 questions

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MULTIPLE CHOICE QUESTION

10 sec • 1 pt

¿Qué condición se debe cumplir para que un límite sea considerado indeterminado?

$\frac{0}{\infty}$

$\frac{\infty}{0}$

$\frac{0}{0}$

$\infty$

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

¿Qué procedimiento usarías para poder resolver el siguiente límite indeterminado?
$\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}$

Sustitución directa

Factorización

Racionalización

No se puede resolver

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

¿Cuál es el resultado al resolver el limite?
$\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}$

$\frac{1}{4}$

$-\frac{1}{4}$

$\frac{0}{0}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Resolviendo el límite siguiente nos da como resultado:
$\lim_{x\rightarrow4}\ \frac{\sqrt{x}-2}{x-4}$

$\frac{0}{0}$

$\frac{1}{4}$

$4$

$-\frac{1}{4}$

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

El conjugado de la expresión
$\sqrt{x-4}-3$ es:

$\sqrt{x-4}+3$

$\sqrt{x+4}-3$

$\sqrt{x+4}+3$

$-\sqrt{x-4}+3$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Resolviendo el limite que a continuación se presenta, nos queda:
$\lim_{x\rightarrow5}\ \frac{x^2-2x-15}{x-5}$

$\frac{0}{0}$

$\frac{1}{5}$

$5$

$-\frac{1}{5}$

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

El siguiente límite es indeterminado, si factorizas las expresiones, te quedaría como:
$\lim_{x\rightarrow-1}\ \frac{x^2-1}{x^2+3x+2}$

$\frac{\left(x+1\right)\left(x-1\right)}{\left(x+2\right)\left(x+1\right)}$

$\frac{\left(x-1\right)\left(x-1\right)}{\left(x+2\right)\left(x+1\right)}$

$\frac{\left(x+1\right)\left(x-1\right)}{\left(x+2\right)\left(x-1\right)}$

$\frac{\left(x+1\right)\left(x-1\right)}{\left(x-2\right)\left(x+1\right)}$

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Resuelve el siguiente límite:
$\lim_{x\rightarrow2}\ \frac{\sqrt{x^2+5}-3}{x^{ }-2}$

$\frac{2}{3}$

$\frac{1}{6}$

$\frac{4}{3}$

$\frac{3}{2}$

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Obtener el valor del límite siguiente:
$\lim_{x\rightarrow-1}\ \frac{x^2+3x+1}{x+1}$

$\frac{-1}{0}$

$0$

$\infty$

$\frac{1}{0}$

10.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

A los límites que mediante la sustitución directa dan como resultado
$\frac{0}{0}$ se les conoce como:

infinitos

error

indeterminados

que no existen

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Límites indeterminados 0/0

¿Qué condición se debe cumplir para que un límite sea considerado indeterminado?

¿Qué procedimiento usarías para poder resolver el siguiente límite indeterminado? lim⁡x→2 x2−4x−2\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}x→2lim​ x−2x2−4​

¿Cuál es el resultado al resolver el limite? lim⁡x→2 x2−4x−2\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}x→2lim​ x−2x2−4​

Resolviendo el límite siguiente nos da como resultado: lim⁡x→4 x−2x−4\lim_{x\rightarrow4}\ \frac{\sqrt{x}-2}{x-4}x→4lim​ x−4x​−2​

El conjugado de la expresión x−4−3\sqrt{x-4}-3x−4​−3 es:

Resolviendo el limite que a continuación se presenta, nos queda: lim⁡x→5 x2−2x−15x−5\lim_{x\rightarrow5}\ \frac{x^2-2x-15}{x-5}x→5lim​ x−5x2−2x−15​

El siguiente límite es indeterminado, si factorizas las expresiones, te quedaría como: lim⁡x→−1 x2−1x2+3x+2\lim_{x\rightarrow-1}\ \frac{x^2-1}{x^2+3x+2}x→−1lim​ x2+3x+2x2−1​

Resuelve el siguiente límite: lim⁡x→2 x2+5−3x−2\lim_{x\rightarrow2}\ \frac{\sqrt{x^2+5}-3}{x^{ }-2}x→2lim​ x−2x2+5​−3​

Obtener el valor del límite siguiente: lim⁡x→−1 x2+3x+1x+1\lim_{x\rightarrow-1}\ \frac{x^2+3x+1}{x+1}x→−1lim​ x+1x2+3x+1​

A los límites que mediante la sustitución directa dan como resultado 00\frac{0}{0}00​ se les conoce como:

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¿Qué procedimiento usarías para poder resolver el siguiente límite indeterminado?
$\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}$

¿Cuál es el resultado al resolver el limite?
$\lim_{x\rightarrow2}\ \frac{x^2-4}{x-2}$

Resolviendo el límite siguiente nos da como resultado:
$\lim_{x\rightarrow4}\ \frac{\sqrt{x}-2}{x-4}$

El conjugado de la expresión
$\sqrt{x-4}-3$ es:

Resolviendo el limite que a continuación se presenta, nos queda:
$\lim_{x\rightarrow5}\ \frac{x^2-2x-15}{x-5}$

El siguiente límite es indeterminado, si factorizas las expresiones, te quedaría como:
$\lim_{x\rightarrow-1}\ \frac{x^2-1}{x^2+3x+2}$

Resuelve el siguiente límite:
$\lim_{x\rightarrow2}\ \frac{\sqrt{x^2+5}-3}{x^{ }-2}$

Obtener el valor del límite siguiente:
$\lim_{x\rightarrow-1}\ \frac{x^2+3x+1}{x+1}$

A los límites que mediante la sustitución directa dan como resultado
$\frac{0}{0}$ se les conoce como: