PRF192

Once the function ends, the control is returned back to the ... function and execution continues from the statement immediately after the function call

a. executing

b.called

c.declared

d.calling

• A

• B

• C

• D

what number is equivalent to -4e3?

a.-4000

b.-400

c..004

d..0004

e.-40

• A

• B

• C

• D

what is the output when the sample code below executed?

#include<stdio.h>

int fn(int v){

if(v==1||v==0)

return 1;

if(v%2==0)

return (fn(v/2)+2);

else

return(fn(v-1)+3);

}

int main()

{

printf("%d\n",fn(5));

return (0);

}

a.6

b.9

c.8

d.7

e.5

• A

• B

• C

• D

• E

which 2 options are correct about the function scanf?

a.EOF indicates that scanf filled all addresses successfully

b. scanf returns the number of addresses successfully filled of EOF

c.return avoid type

d.EOF indicates that scanf did not fill any address AND encountered an end of data character.

• A

• B

• C

• D

what is the output when the sample code below is executed?

int s=35;

printf("%d%d%d",s==35,s+20,s>40)

a.1 35 1

b.1 55 1

c.0 55 0

d.1 55 0

• A

• B

• C

• D

according to the standard C specification, what are the respective minimum sizes (in bytes) of the following two data type: int and long?

a.2,8

b.4,8

c.2,4

d.2,2

• A

• B

• C

• D

what does the following declaration mean (if there are more than one correct answers, choose the best one)

int *ptr[10];

a.array of 10 integer pointers

b.pointed to the array of 10 elements

c.array of 10 pointers

• A

• B

• C

what would happen if the user types in the number 3 and presses Enter when running this program?

main(){

int x=5;

char c;

printf("Enter x=");

scanf("%d",&x);

printf("Calculate square(Y/N):");

c=getchar();

if(c==Y||c==y)

printf("sqr=%d",x*x);

}

a.sqr=9

b.Its depend on whether the user enters 'Y' or not, being asked "calculate square?"

c.sqr=25

d.the program exits without printing the square

• A

• B

• C

• D

what is the output when the sample code below is executed?

int i,j,k,x=0;

for(i=1;i<5;i++)

for(j=0;j<i;++j){

switch(i+j){

case 0:x=x+1;

break;

case 1:

case 2:

case 3: x=x+2;

break;

}}

printf("%d",x);

a.12

b.13

c.10

d.8

e.6

• A

• B

• C

• D

• E

the while loop can be written as a for loop

a.TRUE

b.FALSE

• A. TRUE

• B. FALSE