Hasil dari 8 3 − 5 \frac{8}{3-\sqrt{5}} 3 − 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 8 adalah ....

6 + 2 5 6\ +\ 2\sqrt{5} 6 + 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 + 10 6+\sqrt{10} 6 + 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 − 10 6\ -\sqrt{10} 6 − 1 0 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 − 2 5 6\ -\ 2\sqrt{5} 6 − 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Bentuk sederhana dari 5 3 + 2 \frac{5}{\sqrt{3}\ +\ \sqrt{2}} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> 5 adalah...

5 ( 3 − 2 ) 5\ \left(\sqrt{3}-\sqrt{2}\right) 5 ( 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

3 − 2 \sqrt{3}\ -\ \sqrt{2} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> − 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 + 2 \sqrt{3}+\sqrt{2} 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 ( 3 + 2 ) 5\left(\sqrt{3}+\sqrt{2}\right) 5 ( 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> + 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> )

Jika segitiga yang berwarna biru adalah bayangan dari segitiga berwarna merah, maka transformasi yang tepat adalah … .

B . pencerminan terhadap sumbu Y

A . pencerminan terhadap sumbu X

C. rotasi 90 o dengan pusat titik O

D. rotasi 180 o dengan pusat titik O

Diketahui segitiga ABC dengan koordinat titik A(-4, 1), L(2, 1), dan M(3, 5). Koordinat bayangan jika segitiga dirotasikan 180 ° 180\degree 1 8 0 ° dan berpusat di O(0,0) adalah ...

A'(4, -1), L'(-2, -1), dan M'(-3, -5)

A'(-4, -1), L'(-2, -1), dan M'(-3, -5)

A'(-4, -1), L'(-2, -1), dan M'(3, 5)

A'(4, -1), L'(2, -1), dan M'(3, -5)

A'(-4, 1), L'(-2, 1), dan M'(-3, 5)

PAS Semester Ganjil Matematika Kelas 9

Authored by Y C

Mathematics

9th Grade

CCSS covered

Used 62+ times

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40 questions

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MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Hasil dari $\frac{8}{3-\sqrt{5}}$ adalah ....

$6+\sqrt{10}$

$6\ +\ 2\sqrt{5}$

$6\ -\sqrt{10}$

$6\ -\ 2\sqrt{5}$

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSN.RN.A.2

CCSS.HSA.APR.D.6

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Bentuk sederhana dari $\frac{5}{\sqrt{3}\ +\ \sqrt{2}}$ adalah...

$\sqrt{3}\ -\ \sqrt{2}$

$\sqrt{3}+\sqrt{2}$

$5\left(\sqrt{3}+\sqrt{2}\right)$

$5\ \left(\sqrt{3}-\sqrt{2}\right)$

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSN.RN.A.2

CCSS.HSA.APR.D.6

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Pangkat positif dari $x^{-\frac{5}{2}}y^{-\frac{1}{3}}$ adalah ...

$x^{\frac{5}{2}}y^{\frac{1}{3}}$

$x^{\frac{2}{3}}y^3$

$\frac{1}{x^{\frac{5}{2}}y^{\frac{1}{3}}}$

$\frac{1}{x^{\frac{2}{5}}y^3}$

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Hasil dari $\left(\frac{2a^{-2}b^3}{6c^2}\right)^4$ adalah ....

$\frac{b^{12}}{81a^8c^8}$

$\frac{a^8b^{12}}{81c^8}$

$\frac{16b^{12}}{81a^8c^8}$

$\frac{b^7}{81a^8c^8}$

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSN.RN.A.2

CCSS.HSN.RN.A.1

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

$\frac{-12p^2q^3r\times7r^3q^2p}{42pq^4}=....$

$2p^2qr^4$

$-2p^2qr^4$

$\frac{2p^2r^4}{q}$

$-\frac{2p^2r^4}{q^2}$

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSA.APR.D.6

CCSS.HSA.APR.D.7

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Diketahui persamaan $5^{\left(x-1\right)}=125$ , nilai x yang memenuhi persamaan tersebut adalah ....

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Nilai $\sqrt{196}+216^{\left(\frac{1}{3}\right)}-256^{\left(\frac{1}{4}\right)}=....$

Tags

CCSS.HSN.RN.A.2

CCSS.HSN.RN.A.1

10.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Akar-akar dari persamaan kuadrat $x^2+2x-15=0$ adalah ....

$x=3$ atau $x=5$

$x=-3$ atau $x=-5$

$x=3$ atau $x=-5$

$x=-3$ atau $x=5$

Tags

CCSS.HSA-REI.B.4B

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PAS Semester Ganjil Matematika Kelas 9

Hasil dari $\frac{8}{3-\sqrt{5}}$ adalah ....

Bentuk sederhana dari $\frac{5}{\sqrt{3}\ +\ \sqrt{2}}$ adalah...

Pangkat positif dari $x^{-\frac{5}{2}}y^{-\frac{1}{3}}$ adalah ...

Hasil dari $\left(\frac{2a^{-2}b^3}{6c^2}\right)^4$ adalah ....

$\frac{-12p^2q^3r\times7r^3q^2p}{42pq^4}=....$

Diketahui persamaan $5^{\left(x-1\right)}=125$ , nilai x yang memenuhi persamaan tersebut adalah ....

Nilai $\sqrt{196}+216^{\left(\frac{1}{3}\right)}-256^{\left(\frac{1}{4}\right)}=....$

Nilai diskriminan persamaan kuadrat x² + 6x + 8 = 0

Akar-akar persamaan kuadrat 2x² + 9x + 4 = 0 adalah ...

Akar-akar dari persamaan kuadrat $x^2+2x-15=0$ adalah ....

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PAS Semester Ganjil Matematika Kelas 9

Hasil dari 83−5\frac{8}{3-\sqrt{5}}3−5​8​ adalah ....

Bentuk sederhana dari 53 + 2\frac{5}{\sqrt{3}\ +\ \sqrt{2}}3​ + 2​5​ adalah...

Pangkat positif dari x−52y−13x^{-\frac{5}{2}}y^{-\frac{1}{3}}x−25​y−31​ adalah ...

Hasil dari (2a−2b36c2)4\left(\frac{2a^{-2}b^3}{6c^2}\right)^4(6c22a−2b3​)4 adalah ....

−12p2q3r×7r3q2p42pq4=....\frac{-12p^2q^3r\times7r^3q^2p}{42pq^4}=....42pq4−12p2q3r×7r3q2p​=....

Diketahui persamaan 5(x−1)=1255^{\left(x-1\right)}=1255(x−1)=125 , nilai x yang memenuhi persamaan tersebut adalah ....

Nilai 196+216(13)−256(14)=....\sqrt{196}+216^{\left(\frac{1}{3}\right)}-256^{\left(\frac{1}{4}\right)}=....196​+216(31​)−256(41​)=....

Nilai diskriminan persamaan kuadrat x2 + 6x + 8 = 0

Akar-akar persamaan kuadrat 2x2 + 9x + 4 = 0 adalah ...

Akar-akar dari persamaan kuadrat x2+2x−15=0x^2+2x-15=0x2+2x−15=0 adalah ....

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Hasil dari $\frac{8}{3-\sqrt{5}}$ adalah ....

Bentuk sederhana dari $\frac{5}{\sqrt{3}\ +\ \sqrt{2}}$ adalah...

Pangkat positif dari $x^{-\frac{5}{2}}y^{-\frac{1}{3}}$ adalah ...

Hasil dari $\left(\frac{2a^{-2}b^3}{6c^2}\right)^4$ adalah ....

$\frac{-12p^2q^3r\times7r^3q^2p}{42pq^4}=....$

Diketahui persamaan $5^{\left(x-1\right)}=125$ , nilai x yang memenuhi persamaan tersebut adalah ....

Nilai $\sqrt{196}+216^{\left(\frac{1}{3}\right)}-256^{\left(\frac{1}{4}\right)}=....$

Nilai diskriminan persamaan kuadrat x² + 6x + 8 = 0

Akar-akar persamaan kuadrat 2x² + 9x + 4 = 0 adalah ...

Akar-akar dari persamaan kuadrat $x^2+2x-15=0$ adalah ....