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Basic Differentiation Rules

Authored by Jessica Stewart

Mathematics

11th Grade - University

CCSS covered

Used 145+ times

Basic Differentiation Rules
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12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given  f(x)=3x2+2x−1f\left(x\right)=3x^2+2x-1  , which of the following is the correct derivative?

 f′(x)=6x2+2f'\left(x\right)=6x^2+2  

 f′(x)=6x+2f'\left(x\right)=6x+2  

 f′(x)=6x2+2f'\left(x\right)=6x^2+2  

 f′(x)=6x2+2x2−xf'\left(x\right)=6x^2+2x^2-x  

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The derivative of a function at a given point,  cc  , ie equal to which of the following

The slope of the secant line through c

The slope of the vertical line through c

The slope of the horizontal line through c

The slope of the line tangent to the function at c

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is the correct definition of the Power Rule of derivatives?

Given f(x)=xnf\left(x\right)=x^n , f′(x)=xn−1f'\left(x\right)=x^{n-1}

Given f\left(x\right)=x^n , f′(x)=nxn−1f'\left(x\right)=nx^{n-1}

Given f\left(x\right)=x^n , f′(x)=xn−1nf'\left(x\right)=\frac{x^{n-1}}{n}

Given f\left(x\right)=x^n , f′(x)=nxn−1f'\left(x\right)=\frac{n}{x^{n-1}}

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given f(x)=17f\left(x\right)=17  , what is the derivative of  f(x)f\left(x\right)  ?

 f′(x)=17xf'\left(x\right)=17x  

 f′(x)=17f'\left(x\right)=17  

 f′(x)=0f'\left(x\right)=0  

 f′(x)=17x2f'\left(x\right)=17x^2  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given f(x)=3xf\left(x\right)=3x  , which of the following is the derivative of the function?

 h′(x)=3h'\left(x\right)=3  

 q′(x)=3q'\left(x\right)=3  

 b′(x)=3b'\left(x\right)=3  

 f′(x)=3f'\left(x\right)=3  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derivative of 0?

You can't take the derivative of 0.

0

This is all derivative.

Any constant

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Differentiate with respect to x. y=1x3y=\frac{1}{x^3}  


 ∂y∂x=1x4\frac{\partial y}{\partial x}=\frac{1}{x^4}  

 ∂y∂x=−3x\frac{\partial y}{\partial x}=-3x  

 ∂y∂x=−3x3\frac{\partial y}{\partial x}=-\frac{3}{x^3}  

 ∂y∂x=−3x4\frac{\partial y}{\partial x}=-\frac{3}{x^4}  

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