Quadratic formula with imaginary solutions

What should you do first in solving this equation?

x² + 6x - 13 = 3

• Factor

• Write down: a = 1, b = 6, c = -13

• Subtract 3 from both sides.

• Add 3 to both sides.

Tags

CCSS.HSA-REI.B.4B

If the graph of a quadratic does not touch the x-axis at any point, then it has:

• 1 Real Solution

• 2 Real Solutions

• Half a Solution

• No Real Solution / Imaginary solutions

Tags

CCSS.HSA.REI.B.4

Will the following equation have an IMAGINARY answer
11x²-9x+3=0

• yes
• no

Tags

CCSS.HSA.REI.B.4

CCSS.HSN.CN.C.7

The discriminant is

• aX²  + bX  +  c
• b - 4ac
• b² - 4ac
• b² + 4ac

Tags

CCSS.HSA.APR.B.3

What is the discriminant of 6x² − 2x − 3 = 0

• 76

• 29

• 68

• none of these

Tags

CCSS.HSA.REI.B.4

Simplify √-4

• 2i
• -2i
• 2
• 4i

Tags

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2

 $For\ 2x^2\ -\ 4x\ +\ 3\ =\ 0,\ which\ is\ correct?$  

•  $\frac{4\ \pm\sqrt{-16\ -4\left(2\right)\left(3\right)}}{2\left(2\right)}$  

•  $\frac{-4\ \pm\sqrt{16\ -4\left(2\right)\left(3\right)}}{2\left(2\right)}$  

•  $\frac{4\pm\sqrt{16-4\left(2\right)\left(3\right)}}{4}$  

•  $\frac{4\pm\sqrt{40}}{4}$  

Tags

CCSS.HSA.REI.B.4

if a = 2, b = 4 and c = 10,  what are the errors in

 $\frac{4\ \pm\sqrt{16\ -\ 4\left(2\right)\left(-10\right)}}{2}$  

• The 4 outside the radical should be negative.

• The denominator should be 4, not 2.

• 10 should be positive and not negative.
  
  

• All of the above

Tags

CCSS.HSA.REI.B.4

Which of the following has imaginary solutions?

• $4x^2-6x\ +\ 2\ =\ 0$
  

• $x^2\ +\ 5x\ =\ 8$

• $5x^2-2x\ +\ 6=\ 0$

• $3x^2\ -\ 10x\ -\ 2\ =0$

Tags

CCSS.HSA.REI.B.4

CCSS.HSN.CN.A.1

CCSS.HSN.CN.C.7

CCSS.HSN.CN.C.9

Solve

 $2x^2+4x\ +10=0$  

Simplify answers

•  $-4\ \pm8i$  

•  $-1\pm2i$  

•  $\frac{-4\ \pm8i}{4}$  

•  $\pm8i$  

Tags

CCSS.HSA.REI.B.4

CCSS.HSN.CN.C.7