Search Header Logo

القطع الزائد

Authored by mahmoud wazer

Mathematics

12th Grade

Used 37+ times

القطع الزائد
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

مركز القطع الزائد

 (x1)216(y+2)29=1\frac{\left(x-1\right)^2}{16}-\frac{\left(y+2\right)^2}{9}=1  

(-1,2)

(1,-2)

(-1,-2)

(1,2)

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

مركز القطع الزائد

 (x1)216(y+2)29=1\frac{\left(x-1\right)^2}{16}-\frac{\left(y+2\right)^2}{9}=1  

(-1,2)

(1,-2)

(-1,-2)

(1,2)

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

معادلة المحور القاطع للقطع الزائد

 (y3)24(x+2)25=1\frac{\left(y-3\right)^2}{4}-\frac{\left(x+2\right)^2}{5}=1  

y= -3

x=2

y=3

x= -2

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

معادلتا خطا التقارب للقطع الزائد

 (x+1)24(y3)21=1\frac{\left(x+1\right)^2}{4}-\frac{\left(y-3\right)^2}{1}=1  

 y3=±2(x+2)y-3=\pm2\left(x+2\right)  

 y3=±12(x+2)y-3=\pm\frac{1}{2}\left(x+2\right)  

 y=±12xy=\pm\frac{1}{2}x  

 y=±2xy=\pm2x  

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

طول المحور القاطع في القطع الزائد

 (y3)29(x+1)216=1\frac{\left(y-3\right)^2}{9}-\frac{\left(x+1\right)^2}{16}=1  

3

4

6

8

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Media Image

مركز القطع الزائد الممثل جانبا

(0,-6)

(0,6)

(6,0)

(-6,0)

7.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

في القطع الزائد البؤرتان

 x29(y1)216=1\frac{x^2}{9}-\frac{\left(y-1\right)^2}{16}=1  

 (1,±5)\left(1,\pm5\right)  

 (±5,0)\left(\pm5,0\right)  

 (±5,1)\left(\pm5,1\right)  

 (±5,1)\left(\pm5,-1\right)  

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?