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Trigonometria

Authored by Ana Pereira

Mathematics

11th Grade

Used 26+ times

Trigonometria
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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Um ângulo tem 75°75\degree de amplitude. A sua amplitude, em radianos, é:

 5π6\frac{5\pi}{6}  

 6π5\frac{6\pi}{5}  

 5π12\frac{5\pi}{12}  

 12π5\frac{12\pi}{5}  

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Na circunferência trigonométrica, o ângulo de amplitude  2125° 2125\degree\   pertence ao:

1ºQuadrante

2ºQuadrante

3ºQuadrante

4ºQuadrante

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Na circunferência trigonométrica, o ângulo de amplitude −13π4 rad-\frac{13\pi}{4}\ rad pertence ao: 


1ºQuadrante

2ºQuadrante

3ºQuadrante

4ºQuadrante

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Numa circunferência com 6 cm de raio, um arco com 3 cm de comprimento tem amplitude igual a:

 π rad\pi\ rad  

 π2 rad\frac{\pi}{2}\ rad  

 12 rad\frac{1}{2}\ rad  

 2 rad2\ rad  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Se ] \frac{3\pi}{2},\ 2\pi [ qual das expressões representa um número positivo?

 cos⁡α×tgα\cos\alpha\times tg\alpha  

 tg α+sen αtg\ \alpha+sen\ \alpha  

 senα×cos⁡αsen\alpha\times\cos\alpha  

 tg αsen α\frac{tg\ \alpha}{sen\ \alpha}  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 α∈2ºQ e cos⁡α=−45 pelo que senα+tgα\alpha\in2ºQ\ e\ \cos\alpha=-\frac{4}{5}\ pelo\ que\ sen\alpha+tg\alpha 

 320\frac{3}{20}  

 2027\frac{20}{27}  

 2720\frac{27}{20}  

 −320-\frac{3}{20}  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

O contradomínio da função f(x)=5−2sen(x−π3)f\left(x\right)=5-2sen\left(x-\frac{\pi}{3}\right)  

é:

 [−3,7]\left[-3,7\right]  

 [2,5]\left[2,5\right]  

 [−1,1]\left[-1,1\right]  

 [3,7]\left[3,7\right]  

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