Algebra 2 In Class Check day 14

If given the equation y = 3(x + 5)² - 4, what is the vertex of the parabola?

• (5, -4)

• (-5, -4)

• (-15, -4)

• (15, -4)

What is the equation of this graph?

• f(x) = (x -5)² + 1
• f(x) = (x - 1)² - 5
• f(x) = (x + 1)² - 5
• f(x) = (x + 5)² +1

Tags

CCSS.HSF-IF.C.7A

Which equation has a vertex of (-3, 4)?

• y = 2(x+3)² + 4
• y = (x+3)² - 4
• y = (x-3)² + 4
• y = 2(x - 3)² + 4

Tags

CCSS.8.F.A.1

CCSS.8.F.A.2

CCSS.8.G.A.3

What is the axis of symmetry of the given function?

• y = 1
• y = -1
• x = 1
• x = -1

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

What is the equation of the graph?

• $y=-\left(x+2\right)^2+5$

• $y=-\left(x-2\right)^2+5$
  

• $y=-\left(x+2\right)^2-5$
  

• $y=-\left(x-2\right)^2-5$
  

MARK ALL TRUE STATEMENTS:

 $y=\left(x-3\right)^2+5$  

• Vertex (3,5)

• Right 3, Up 5

•  $Domain\ x\ge3$  
  

•  $Range\ y\ge5$  

Which statement is FALSE?

 $y=-2\left(x-1\right)^2+5$  

• Vertex is (1,5)

• ROX

• Vertical compress of 2

• Right 1 and up 5

Find the y-intercept:

 $y=-2\left(x-1\right)^2+5$  

• (0,-5)

• (0,-1)

• (0,3)

• (0,7)

Find the x-intercepts:

 (solve by square root)

 $y=\left(x+1\right)^2-4$  

• (-1,0) and (3,0)

• (1,0) and (-3,0)

• (-1,0) and (-4,0)

• (3,0) and (5,0)

Find the x-intercepts:

 (solve by square root)

 $y=2\left(x-2\right)^2-18$  

• (-1,0) and (5,0)

• (-1,0) and (1,0)

• (1,0) and (-5,0)

• (2,0) and (11,0)