integrale nedefinite si definite

integrale nedefinite si definite

12th Grade

10 Qs

quiz-placeholder

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integrale nedefinite si definite

integrale nedefinite si definite

Assessment

Quiz

Mathematics

12th Grade

Medium

Created by

ALINA COLCER

Used 20+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 (6x2+10x7)dx = ...\int_{ }^{ }\left(6x^2+10x-7\right)dx\ =\ ...  

 2x3+5x27x+c2x^3+5x^2-7x+c  

 3x2+5x7x+c3x^2+5x-7x+c  

 2x3+5x27+c2x^3+5x^2-7+c  

 2x3+10x7+c2x^3+10x-7+c  

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

  32x5dx = ...\int_{ }^{ }\ \frac{3}{2x^5}dx\ =\ ...  

 32x6+c-\frac{3}{2x^6}+c  

 32x4+c\frac{3}{2x^4}+c  

 38x3+c\frac{3}{8x^3}+c  

 38x4+c-\frac{3}{8x^4}+c  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 (2x5)6dx = ...\int_{ }^{ }\left(2x-5\right)^6dx\ =\ ...  

 17(2x5)7+c\frac{1}{7}\left(2x-5\right)^7+c  

 (2x5)7+c\left(2x-5\right)^7+c  

 114(2x5)7+c\frac{1}{14}\left(2x-5\right)^7+c  

 27(2x5)7+c\frac{2}{7}\left(2x-5\right)^7+c  

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

  x(12x2)6 dx = ...\int_{ }^{ }\ \frac{x}{\left(1-2x^2\right)^6}\ dx^{\ }=\ ...  

 120(12x2)5+c-\frac{1}{20\left(1-2x^2\right)^5}+c  

 120(12x2)5+c\frac{1}{20\left(1-2x^2\right)^5}+c  

 15(12x2)5+c-\frac{1}{5\left(1-2x^2\right)^5}+c  

 15(12x2)5+c\frac{1}{5\left(1-2x^2\right)^5}+c  

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 xx21 dx = ...\int_{ }^{ }x\sqrt{x^2-1}\ dx\ =\ ...  

 x3(x21)32+c\frac{x}{3}\left(x^2-1\right)^{\frac{3}{2}}+c  

 13(x21)23+c\frac{1}{3}\left(x^2-1\right)^{\frac{2}{3}}+c  

 13(x21)32+c\frac{1}{3}\left(x^2-1\right)^{\frac{3}{2}}+c  

 x3(x21)23+c\frac{x}{3}\left(x^2-1\right)^{\frac{2}{3}}+c  

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 2x3(x41)3 dx =...\int_{ }^{ }2x^3\left(x^4-1\right)^3\ dx\ =...  

 12(x41)4+c\frac{1}{2}\left(x^4-1\right)^4+c  

 14(x41)4+c\frac{1}{4}\left(x^4-1\right)^4+c  

 16(x41)4+c-\frac{1}{6}\left(x^4-1\right)^4+c  

 18(x41)4+c\frac{1}{8}\left(x^4-1\right)^4+c  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

 14(1x2x)dx = ...\int_1^4\left(\frac{1}{x^2}-\sqrt{x}\right)dx\ =\ ...  

 6718\frac{67}{18}  

 4712-\frac{47}{12}  

 2411-\frac{24}{11}  

 4021\frac{40}{21}  

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