DOL: Systems of linear and quadratic equations

First step is to plug in the quadratic equation into the linear equation. Which is correct?

• $\left(x^2+3x-5\right)-x=3$

• $y-\left(x^2+3x-5\right)=3$
  

• $y-x=x^2+3x-5$
  

Tags

CCSS.HSA.REI.C.7

Second step is to move all terms to the left side of the equation and combine like term. Which is correct?

•  $x^2+2x-8=0$ 

•  $x^2+4x-8=0$ 
  

•  $x^2+x+8=0$ 
  

Tags

CCSS.HSA-REI.B.4B

Third step is to apply the x-method to find the factors. Which are correct?

•  $\left(x+4\right)\left(x-2\right)=0$ 

•  $\left(x-4\right)\left(x+2\right)=0$ 
  

•  $\left(x+4\right)\left(x+2\right)=0$ 
  

Tags

CCSS.HSA-REI.B.4B

Fourth step is to identify the zeros/x-values. Which are correct?

•  $x=-4\ or\ x=2$ 

•  $x=4\ or\ x=-2$ 
  

•  $x=23\ or\ x=15$ 
  

Tags

CCSS.HSA.REI.C.7

Fifth step is to find the values of y by plugging in x values into one of the original equations. Which are correct?

•  $y=-1\ or\ y=5$ 

•  $y=1\ or\ y=-5$ 
  

•  $y=8\ or\ y=-3$ 
  

Tags

CCSS.HSA.REI.C.7

Sixth step is to identify the solutions now that we have the x and y values. Which are correct?

•  $\left(-4,-1\right)\ or\ \left(2,5\right)$ 

•  $\left(-1,-4\right)\ or\ \left(5,2\right)$ 
  

•  $\left(4,1\right)\ or\ \left(-2,-5\right)$ 
  

Tags

CCSS.HSA.REI.C.7