Search Header Logo

Calculus Derivative using Chain Rule Basic

Authored by Adeyemi Aderinto

Mathematics

10th Grade - University

CCSS covered

Used 30+ times

Calculus Derivative using Chain Rule Basic
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative of  f(x) = (x6 + 4)5

f '(x) = 5x5(x4 + 4)4
f '(x) = 6x5(x6 + 4)4
f '(x) = 30x5(x6 + 4)4
f '(x) = 30x6(x6 + 4)4

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative of f(x)=(x3 - 2x)2

and simplify

6x5 - 12x3+8x

6x5 - 16x3+8x

x6-4x4+4x2

6x5 - 16x3-8x

Tags

CCSS.HSA.APR.A.1

3.

MULTIPLE CHOICE QUESTION

15 mins • 12 pts

find y' for y= (2x+1)10

10(2x+1)9

20(2x-1)9

20(2x+1)10

20(2x+1)9

Tags

CCSS.HSA.APR.C.5

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Media Image

Media Image
Media Image
Media Image
Media Image

Tags

CCSS.HSA.APR.A.1

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative f(x) = (x2 + 2x)5

f'(x) = 5(2x+2)4

f'(x) = 5(x2 + 2x)4

f'(x) = 5(x2 + 2x)4(2x)

f'(x) = (10x + 10) (x2 + 2x)4

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

 dydx if y=(2x2+4)3\frac{dy}{dx}\ if\ y=\left(2x^2+4\right)^3  Find

 (12x+4)(2x2+4)2\left(12x+4\right)\left(2x^2+4\right)^2  

 3(2x2+4)23\left(2x^2+4\right)^2  

 12x(2x2+4)212x\left(2x^2+4\right)^2  

 12(2x2+4)212\left(2x^2+4\right)^2  

Tags

CCSS.HSA.APR.A.1

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Find the derivative of following with respect to x:

f(x) = (x6 + 4)5

f '(x) = 5x5(x4 + 4)4

f '(x) = 6x5(x6 + 4)4

f '(x) = 30x5(x6 + 4)4

f '(x) = 30x6(x6 + 4)4

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?