a = 5 – 7 b , 則 b = a=5–7b,\ 則b= a = 5 – 7 b , 則 b =

5 − a 7 \frac{5-a}{7} 7 5 − a

a − 5 7 \frac{a-5}{7} 7 a − 5

7 − a 5 \frac{7-a}{5} 5 7 − a

令b成為公式 a + 4 3 = b + 1 2 \frac{a+4}{3}=\frac{b+1}{2} 3 a + 4 = 2 b + 1 的主項

b = 2 a + 5 3 b=\frac{2a+5}{3\ } b = 3 2 a + 5

b = 2 a + 5 4 b=\frac{2a+5}{4\ } b = 4 2 a + 5

b = a + 5 3 b=\frac{a+5}{3\ } b = 3 a + 5

b = 2 a + 6 3 b=\frac{2a+6}{3\ } b = 3 2 a + 6

令y成為 k = 3 x − y y k=\frac{3x-y}{y} k = y 3 x − y 的主項

y = 3 x x + 1 y=\frac{3x}{x+1} y = x + 1 3 x

y = 3 x 2 x + 1 y=\frac{3x}{2x+1} y = 2 x + 1 3 x

y = x x + 1 y=\frac{x}{x+1} y = x + 1 x

y = 3 x + 1 y=\frac{3}{x+1} y = x + 1 3

若 h = 3 − 5 k + 4 h=3-\frac{5}{k+4} h = 3 − k + 4 5 ,則 k =

4 h − 7 3 − h \frac{4h-7}{3-h} 3 − h 4 h − 7

4 h − 17 3 − h \frac{4h-17}{3-h} 3 − h 4 h − 1 7

4 h − 7 3 + h \frac{4h-7}{3+h} 3 + h 4 h − 7

4 h − 17 3 + h \frac{4h-17}{3+h} 3 + h 4 h − 1 7

若 k = 3 − 2 y y k=\frac{3-2y}{y} k = y 3 − 2 y ，以下哪一項才是正確的移項步驟？

k + y = 3 − 2 y k+y=3-2y k + y = 3 − 2 y

若 y = 3 2 + k y=\frac{3}{2+k} y = 2 + k 3 ，以下哪一項才是正確的移項步驟？

y 3 = 1 2 + k \frac{y}{3}=\frac{1}{2+k} 3 y = 2 + k 1

y\left(2+k\right)=3 y ( 2 + k ) = 3

3 y = 2 + k \frac{3}{y}=2+k y 3 = 2 + k

3 y = 1 2 + k \frac{3}{y}=\frac{1}{2+k} y 3 = 2 + k 1

若 x + a = 16 x+a=16 x + a = 1 6 ，以下哪一項是正確的移項步驟？

x = 16 a x=\frac{16}{a} x = a 1 6

x = 16 − a x=\frac{16}{-a} x = − a 1 6

若 x + 4 y = 16 x+4y=16 x + 4 y = 1 6 ，以下哪一項是正確的移項步驟？

4 y = 16 − x 4y=16-x 4 y = 1 6 − x

x = 16 4 y x=\frac{16}{4y} x = 4 y 1 6

x = 16 − 4 y x=\frac{16}{-4y} x = − 4 y 1 6

x = 16 + 4 y x=16+4y x = 1 6 + 4 y

若 x 4 − 2 = y \frac{x}{4}-2=y 4 x − 2 = y ，以下哪一項是正確的移項步驟？

x − 2 ( 4 ) 4 = y \frac{x-2\left(4\right)}{4}=y 4 x − 2 ( 4 ) = y

x − 2 ( 4 ) = 4 y x-2\left(4\right)=4y x − 2 ( 4 ) = 4 y

x 4 = y + 2 \frac{x}{4}=y+2 4 x = y + 2

x − 2 = 4 y x-2=4y x − 2 = 4 y

若 − 7 y = 2 x − 16 -7y=2x-16 − 7 y = 2 x − 1 6 ，以下哪一項是正確的移項步驟？

1 = 2 x − 16 − 7 y 1=\frac{2x-16}{-7y} 1 = − 7 y 2 x − 1 6

0 = 2 x − 16 + 7 y 0=2x-16+7y 0 = 2 x − 1 6 + 7 y

y = 2 x − 16 7 y=\frac{2x-16}{7} y = 7 2 x − 1 6

0 = 2 x − 16 − 7 y 0=\frac{2x-16}{-7y} 0 = − 7 y 2 x − 1 6

1 = 2 x − 16 + 7 y 1=2x-16+7y 1 = 2 x − 1 6 + 7 y

2021_F2_Maths_CH4_主項變換

Authored by shun lin

Mathematics

7th - 8th Grade

Used 5+ times

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20 questions

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MULTIPLE CHOICE QUESTION

5 mins • 1 pt

令 a 成為公式 a + b = c的主項

a = c - b

a = b - c

a = b + c

a = bc

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

令 a 成為公式a + b = c + d 的主項

a = c + d - b

a = b + c + d

a = b + c - d

a = c - b - d

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

令 w 成為公式 A = lw 的主項

w = A/l

w = l/A

w = A - l

w = Al

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

令 x 成為公式 y = mx + c 的主項

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

令 x 成為公式 N = (180 + x)/2 的主項

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

令 r 成為公式 C = 2πr 的主項

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

令 r 成為公式 A = πr² 的主項

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$a=5–7b,\ 則b=$

$\frac{5-a}{7}$

$\frac{a-5}{7}$

$\frac{7-a}{5}$

$\frac{a+7}{5}$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

$a=\frac{d}{t^2},\ \ \ 則\ d=$

$a^2t$

$at^2$

$at$

$a^2t^2$

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2021_F2_Maths_CH4_主項變換

令 a 成為公式 a + b = c的主項

令 a 成為公式a + b = c + d 的主項

令 w 成為公式 A = lw 的主項

令 x 成為公式 y = mx + c 的主項

令 x 成為公式 N = (180 + x)/2 的主項

令 r 成為公式 C = 2πr 的主項

令 r 成為公式 A = πr2 的主項

如 2x - 3y = 6z, 則 y =

a=5–7b, 則b=a=5–7b,\ 則b=a=5–7b, 則b=

a=dt2, 則 d=a=\frac{d}{t^2},\ \ \ 則\ d=a=t2d​, 則 d=

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令 r 成為公式 A = πr² 的主項

$a=5–7b,\ 則b=$

$a=\frac{d}{t^2},\ \ \ 則\ d=$