Quadratic applications

Quadratic applications

11th Grade

16 Qs

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Quadratic applications

Quadratic applications

Assessment

Quiz

Mathematics

11th Grade

Practice Problem

Medium

CCSS
HSA.REI.B.4, HSA.SSE.A.1, HSF.IF.B.4

+8

Standards-aligned

Created by

Mary Basham

Used 150+ times

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16 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial (starting) height of an object following this path?  h(t) = -16t2 +20t + 6

-16 feet 
0 feet
20 feet 
6 feet 

Tags

CCSS.HSA.SSE.A.1

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If path of a projectile is modeled by: 
h(t) = -16t2 + 20t +6, what is the height after 1 second? 

6 feet 
20 feet 
10 feet 
4 feet 

Tags

CCSS.HSA.SSE.A.1

CCSS.HSF.IF.A.1

CCSS.HSF.IF.A.2

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

To calculate the TIME that a maximum height occurs, you should use: 

-b/(2a) 
Quadratic formula 
the c value 
0

Tags

CCSS.HSA.REI.B.4

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For that same projectile, at what TIME does the maximum height occur? 
h(t) = -16t2 + 20t + 6 

0 seconds 
.625 seconds 
160 seconds 
2 seconds 

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

To calculate the maximum height, you should: 

Use the time you got from -b/(2a) and plug it in for each "t" 
-b/(2a) 
use the c value 
use the b value 

Tags

CCSS.HSA.REI.B.4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the maximum height for that same projectile? (time of maximum height was .625) 
h(t) = -16t2 + 20t + 6 

8.5 feet 
12.25 feet 
24.75 feet 
6 feet 

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.1

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If we are trying to find out when an object hits the GROUND, what should we put in for "h"? 

0
1
2
3

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

CCSS.HSA.SSE.A.1

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